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jih
matlab,Mathimatics-Numerical algorithms
- 2010-08-30 16:25:44下载
- 积分:1
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filter_thesis
filter synthesis -parts of the program, need to be completed later
- 2015-04-14 09:46:31下载
- 积分:1
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果蝇优化算法
根据果蝇优化算法得到极速学习机隐层神经元的数目依据得到的隐层神经元数目和极限学习机的方法对训练样本和测试样本进行训练学习。(According to the fruit flies optimization algorithm to get extreme learning machine based on the number of hidden layer neurons of hidden layer neurons number and extreme learning machine method of training samples and testing samples to carry on the training study.)
- 2016-11-02 15:01:12下载
- 积分:1
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PCNNtuxiangyasuo
PCNN的相关算法的实现:一定条件下PCNN动态行为的分析;一种基于脉冲耦合神经网络的最短路径算法(PCNN algorithm related: under certain conditions, the analysis of dynamic behavior PCNN a pulse coupled neural networks based on shortest path algorithm)
- 2008-03-19 15:03:56下载
- 积分:1
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matlab
说明: MATLAB 模糊控制PID调节 逻辑工具箱函数说明(MATLAB模糊逻辑工具箱函数)
- 2010-04-07 08:35:45下载
- 积分:1
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2b9f66cc3637
SHORTEST PATH PROGRAM
- 2012-04-03 23:19:46下载
- 积分:1
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di10zhang-
基于matlab数字图像处理技术随书源代码第10章(Based on matlab digital image processing technology with the book source code Chapter 10)
- 2013-11-28 09:40:15下载
- 积分:1
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windfarm
本资料包括风电场一年内的风速实测数据,并根据实测数据对风电场风速和输出功率进行预测和建模仿真,希望对大家有帮助。(This information, including wind velocity measured data within the electric field of the year, and based on the measured data on wind speed and power output forecasting and modeling and simulation, we hope to help.)
- 2014-02-16 10:22:56下载
- 积分:1
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By-Arthur7777777777777777
女声 男声转换的程序 用matlab做的,运行无差错,供大家参考(Female male conversion process using matlab to do, running error-free, for your reference)
- 2014-11-25 22:11:25下载
- 积分:1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置!Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机;
变异位数统一取为4;
Nc=20,28,36,44,individuals for crossover(交换的个数)。Nm=1,5,10,15, individuals for mutation(变异的个数)。(To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分:1