Plotting_Tutorial_New1

将加速度积分成速度位移，并且滤波，很好用(Displacement velocity integral of the acceleration and filtering, the good)

该程序介绍了MATLAB中怎么样生成模糊控制规则与控制量查询(The program introduces MATLAB, how kind of fuzzy control rules and control the generation of inquiries)

haar小波分析的类，只有头文件，输入为一个序列的信号，输出为haar小波分解后的各级参数(haar wavelet class)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

说明：  简单例子A simple exampleA simple example(A simple example)

gabor 小波matlab变换,与C结合(gabor wavelet transform matlab, and C combined)

用Matlab实现人脸检测的功能，程序正确，可以运行，包含测试图片(Face detection using Matlab functions implement the program correctly, you can run, including the test images)

利用matlab进行五点三次法平滑处理(时域和频域)(Using matlab 5.3 times France smoothing process (time domain and frequency domain))

this code is a matrix with 4 operation

NSIS jiemian仿酷狗安装包实例(Imitation cool dog package instance)