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w_r
用MATLAB编写的加密代码 先将源文件翻译成ASCII码 在对其进行加密(Encrypted code written with MATLAB source file first translated into ASCII code in its encrypted)
- 2010-07-07 16:46:31下载
- 积分:1
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MATLAB
说明: matlab的一些基础讲解,适用于初学者。主要是关于在数字信号处理课程中的应用。(to explain some basic matlab for beginners. Mainly on the course in digital signal processing applications.)
- 2011-03-13 13:44:48下载
- 积分:1
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ACS_Assignment_1
sliding mode control files for advanced control system
- 2011-05-16 19:49:23下载
- 积分:1
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math-model-analysis
这是数学建模中会用到的各种算法的总结书,内容很好,希望能有所帮助。(This is the mathematical modeling will be used in a variety of algorithms summarize the book, the content well, hoping to help.)
- 2011-07-20 16:26:11下载
- 积分:1
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Cognitive-radio
基于遗传算法的认知无线电的实现,充分利用利用遗传算法的人工智能优化,对认知无线电的通信参数自适应调整予以实现。(Based on genetic algorithm, the realization of cognitive radio, full use of genetic algorithm to optimize the artificial intelligence, adaptive adjustment of the communication parameters of cognitive radio to be realized.)
- 2016-09-29 10:17:45下载
- 积分:1
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graph_sman
These four files are intended for addingdeleting nodes and edges in biograph object
- 2013-01-07 23:39:11下载
- 积分:1
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st
说明: 广义S变换程序 广义S变换具有短时傅里叶变换与小波变换的特性 其反变换与FFT紧密相连(Generalized program generalized S transform S transform with short-time Fourier transform and wavelet transform features of its inverse transform is closely linked with the FFT)
- 2011-11-12 19:42:16下载
- 积分:1
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Solution-of-algebraic-equations
代数方程组的解法,matlab,希望对大家有用(Solution of algebraic equations, matlab)
- 2012-06-27 10:53:47下载
- 积分:1
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communication-system(MATLAB-version)
现代通信系统(matlab版)书中所有源码。这本书能够帮助初学通信原理的同学深入体会原理的内涵。(Modern communication systems (matlab version) book all source code. This book will help novice students in-depth experience of communication theory principles connotations.)
- 2013-07-23 15:36:54下载
- 积分:1
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111
function pi = solve2(count,m,cc)
借助布冯投针实验 仿真求pi的值
pi=0
frq=0
randNo = binornd(1,cc,1,m)
pro=zeros(1,count)
for j=1:count
for i = 1:m
if randNo(1,i) == 1
frq = frq + 1
end
pro(i) = frq/i
end
pi = (2*m)/frq
pro(j) = pi
end
pro = pro,num =1:count
plot(num,pro) (function pi = solve2 (count, m, cc) to vote with Buffon needle experiment simulation find the value of pi pi = 0 frq = 0 randNo = binornd (1, cc, 1, m) pro = zeros (1, count) for j = 1: count for i = 1: m if randNo (1, i) == 1 frq = frq+ 1 end pro (i) = frq/i end pi = (2* m )/frq pro (j) = pi end pro = pro, num = 1: count plot (num, pro) )
- 2011-05-24 15:39:41下载
- 积分:1