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LTEchannelmatrix
该代码是lte信道的仿真源码,用于仿真lte上行链路(The code is emulation lte source channel for the uplink simulation lte)
- 2010-12-17 10:40:32下载
- 积分:1
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anttsp
说明: 这是蚂蚁算法求解TSP的源代码,Matlab中实现。(This is the ant algorithm for TSP source code, Matlab achieve.)
- 2006-04-04 15:17:15下载
- 积分:1
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optimization-methods
本书介绍了非线性最优化问题的基本理论和算法,以及主要算法的matlab程序(This book describes the nonlinear optimization problem of the basic theory and algorithms, as well as the main algorithm matlab program)
- 2013-08-10 08:24:30下载
- 积分:1
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ecg-beat-detection-in-matlab
Ecg beat detection in matlab
- 2014-01-23 17:00:43下载
- 积分:1
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DS_SpreadSpectrum
用Simulink搭建的直接序列扩频(DS-SS)系统仿真模型,仿真结果比较理想。(A simulation on DS-Spread Spectrum communication system based on Simulink toolbox.)
- 2009-03-19 15:38:57下载
- 积分:1
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fast_cs_SRM_v1.1
used to reconstruct the origernal signal from random measurement(compressive sensing reconstruction program)
- 2009-03-24 18:17:18下载
- 积分:1
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hysthresh
matlab code-Function performs hysteresis thresholding of an image.
All pixels with values above threshold T1 are marked as edges
All pixels that are adjacent to points that have been marked as edges
and with values above threshold T2 are also marked as edges. Eight
connectivity is used.
- 2009-10-30 22:50:53下载
- 积分:1
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RBFMATLAB
说明: rbf源码说明有例子,有详细解说,说明步骤和原理。希望对大家有用(有例子,有详细解说,说明步骤和原理。希望对大家有用)
- 2010-05-05 10:17:46下载
- 积分:1
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LiZiqun
这是一个基于粒子群算法来寻找图片上的园的圆心,通过自己设置参数,可以在较短的时间内较为精确的找到一个图所有圆的圆心(It is used to find the location of circles in a complicant map. For this fuction, you can set some paraement yourself and it will return the result in a very short time. )
- 2011-05-07 14:20:00下载
- 积分:1
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MadHG
利用函数MadHG生成规则LDPC码的校验矩阵H,其行重为6,列重为3,行数为列数一半(行数越大越好),H中任意两列没有围长为4的圈,并得到H对应的生成矩阵G,可以保证mod(G*H ,2)=0。使用方法为:[H,G] = MadHG(m,n,x),x= 1(得到的G左半部分为单位阵) or 2(G右半部分为单位阵),(use function MadHG Generation rules LDPC check matrix H, re-6, series of three, out for a few half of the number (A bigger the better), H 2 arbitrary no girth of the four circles, H counterparts and with the formation of matrix G, we can be assured of mod (G* H, 2) = 0. To be used : [H, G] = MadHG (m, n, x), x = 1 (the G part of the Left Front units) or 2 (G right half of the units RUF),)
- 2007-05-12 10:54:46下载
- 积分:1