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DerivativePoint
应用多元高斯声束叠加方法建立粉末合金构件的声场模型(sound field simulation sound field simulation sound field simulation )
- 2012-05-03 21:10:31下载
- 积分:1
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1001-0548(2012)02-0208-04
宽带CIC抽取滤波器的一种改进方法1001-0548(2012)02-0208-04(Improved Method for Wideband CIC Decimation Filters
)
- 2014-02-01 23:32:08下载
- 积分:1
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fiber mode
说明: 光纤LP模式,光纤模式计算,纤芯模式,有效折射率(Fiber LP mode, fiber mode calculation, fiber core mode, effective refractive index)
- 2021-02-25 22:09:38下载
- 积分:1
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xx
说明: 标准图像,包含多幅用于matlab的标准图像(The standard image, contains many standard for matlab image)
- 2015-01-27 17:30:02下载
- 积分:1
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ibm
Paradigms Theory and Applications using MATLAB
- 2012-04-20 19:19:20下载
- 积分:1
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yinzhang
一个关于印章识别的程序,能很好的学习Gui用的模式识别中判别函数法。(A seal of recognition on the program can be good learning Gui with the discriminant function method in pattern recognition.)
- 2011-06-27 11:23:03下载
- 积分:1
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EMD
EMD 方法在理论上可以应用于任何类型的信号的分解, 因而在处理非平稳及非线性数据上,具有非常明显的优势,适合于分析非线性、非平稳信号序列,具有很高的信噪比。(EMD decomposition method in theory can be applied to any type of signal, which in the non-stationary and nonlinear data, with a very distinct advantage, suitable for analyzing nonlinear and non-stationary signal sequence, with a high signal to noise ratio .)
- 2014-11-25 18:54:48下载
- 积分:1
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序贯蒙特卡洛概率假设密度滤波器的matlab仿真实现SMC_PHD
序贯蒙特卡洛概率假设密度滤波器的matlab仿真实现(the simulation of sequential monte carlo probability hypothesis density filter)
- 2021-03-05 14:19:31下载
- 积分:1
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Gram-Schmidt_Process
施密特正交化过程,根据文献中的方法进行matlab编程实现(Schmidt orthogonalization process)
- 2011-01-02 16:23:28下载
- 积分:1
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para
说明: 抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.
(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2005-12-03 18:11:10下载
- 积分:1