source-position

说明：  AUTOMATIC AIR PRESSURE MONITORING SYSTEM it will roll at a different wheel speed than the other tires.

说明：  基于gulp的打包流程，简单实用，条例清楚(Packaging process based on gulp)

说明：  上传代码为猴群算法的基础源代码，分了主函数和爬过程、望过程、和空翻过程。(Is the source code of the monkey group algorithm.)

关于一些OPC的资源,提供出来大家共享!-some of the OPC resources to provide up share!

TC中的串口编程-Serial Programming

无线通信基础的书，中英文版，从入门到精通(wireless communication book)

说明：  无线通讯FPGA自留学习，内含matlab代码，Verilog代码以及缩略语说明(Wireless communication FPGA self-learning, including MATLAB code, Verilog code and acronym description)

matlab code for CST about homework

说明：  球粒子Mie散射（含蒙特卡洛仿真）-Kevin Zhu(Mie scattering of spherical particles (including Monte Carlo simulation) - Kevin Zhu)

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.