登录
首页 » matlab » gear

gear

于 2012-11-02 发布 文件大小:1KB
0 308
下载积分: 1 下载次数: 41

代码说明:

  关于齿轮设计的程序,计算齿轮传动尺寸,求得变位齿轮计算数据,齿轮副啮合角和渐开线函数值,几何尺寸(the program was used to caculate gear)

文件列表:

gear.m,2798,2012-10-31

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • plate_vibrate_process
    本程序主要根据有限元法编写,可以求解薄板的振动和静力分析问题(This procedure mainly based on the preparation of the finite element method can solve the plate vibration and static analysis of the problem)
    2011-06-10 20:15:16下载
    积分:1
  • MachineLearning
    说明:  机器学习的鸢尾花数据集的应用逻辑回归算法分类(Classification of iris data set by logical regression algorithm)
    2021-03-22 13:59:32下载
    积分:1
  • cordic_1-0
    在通訊系統中常見到的cordic,是個用很少複雜度就能實現三角函數的電路,檔案中有C語言的CORDIC程式(In the communication system common to cordic, is a little complex to use trigonometric functions will be able to realize the circuit, the file has C language program CORDIC)
    2009-02-15 05:19:59下载
    积分:1
  • single
    使用奇异值分解来帮助求解最小二乘问题,特别是在方程系数矩阵不满秩的情况下。(SGELSD computes the minimum-norm solution to a real linear least * squares problem: * minimize 2-norm(| b- A*x |) * using the singular value decomposition (SVD) of A. A is an M-by-N * matrix which may be rank-deficient.)
    2009-10-30 16:32:14下载
    积分:1
  • jiech
    这是一个关于高精度阶乘的程序,测试可用!!!(This is a program on the high-precision factorial test available! ! !)
    2012-09-27 07:35:40下载
    积分:1
  • Euler_DG_Quadrilateral_2D
    自己写了一个二维Euler方程的间断有限元程序 上次发了一个三角形单元的程序 因为不是曲边单元 所以在圆柱后面容易形成涡 现在把程序改为曲边四边形单元了 没有涡出现 单元是8节点四边形单元 节点编号顺序是 1 5 2 6 3 7 4 8 也就是四个角点依次 是1 2 3 4 然后是边的中点编号 5 6 7 8. 时间推进采用 Runge-Kutta 方法 数值通量采用全局Lax-Friedrichs通量 仍然不能捕捉激波 因为没有做重构或者加人工粘性 等这个做出来了 再发一次。 程序没有进行优化 比如说内存的消耗没有优化 比如直边单元的边界积分仍然采 用了曲边的积分方法 增加了计算量 比如面积分、线积分都是采用的是Gauss- Legendre-Lobatto积分 积分精度会比一般的Gauss-Legendre积分精度低一阶 等 等问题。 二维的 纯属交流性质 就没有考虑这些问题 ^_^ 如果物面全部是直边 那么只要改变一个参数N 就可以获得不同的计算精度 且具 有谱精度 因为单元的节点是Gauss-Legendre-Lobatto积分点。 其实就是谱元法 (物面是曲边的情况我不清楚是不是也可以通过提高基函数的阶数 也就是增加N 来提高计算精度)(Wrote a two-dimensional Euler equations with discontinuous finite element program Last made ​ ​ a triangular element of the program, not curved edge unit is so easy to form a vortex in the cylinder behind the Program to curved edge quadrilateral element vortices appear Unit is the order of 8-node quadrilateral element node number is 15,263,748 which is the four corners of the points in turn Is 1234 and then the side of the midpoint of the number 5678. Time promote the use of Runge-Kutta method Numerical flux of the overall situation of Lax-Friedrichs, flux Still can not capture the shock wave did not do the reconstruction or artificial viscosity do it Zaifayici. The program is not optimized for example, memory consumption is not optimized such as straight-edge boundary integral of the unit is still mining Integral method to increase the amount of computation such as surface integral with a curved edge, the line integral using the Gauss- The Legendr)
    2021-01-29 12:58:40下载
    积分:1
  • shuzhijisuan
    数值计算实例,主要有LU分解,龙格库塔法,高斯分解法,欧拉法,曲线拟合,曲线插值(Numerical example)
    2014-01-03 10:38:53下载
    积分:1
  • cycliiqafb
    三次样条插值的C语言算法,但是总是数据溢出(Cubic spline interpolation C language algorithm, but always data overflow)
    2018-11-09 21:05:00下载
    积分:1
  • minonlntool
    说明:  多阶段物流配送问题GA解法,用于物流配送中心选址问题的解决(logistics center location)
    2021-03-04 20:59:31下载
    积分:1
  • fenerzhizhisuanfa
    说明:  这是一个ACM试题中的算法,叫分而治之算法,上面有PPT还有实例代码,希望喜欢ACM的同学可以喜欢(This is a Question in the ACM algorithm, called divide and conquer algorithms, there are examples of the code above, there are PPT hope that students like to be like the ACM)
    2010-03-26 12:38:25下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载