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biaogao4
机械设计及理论 转子动力学中对轴承的研究(Mechanical Design and Theory Rotor Dynamics)
- 2013-10-08 10:47:31下载
- 积分:1
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diskid32
獲取windows系統硬盤的一些信息,可以獲取到SN,FW,MODEL,等等信息(Get some information windows system hard disk, you can get to the SN, FW, MODEL, and so forth)
- 2014-11-04 19:54:34下载
- 积分:1
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gongetidu
共轭梯度法的matlab实现,给出任意的一个对称矩阵,可通过较小的迭代次数得到所要求精度的数值解(Conjugate gradient method matlab to achieve, given any symmetric matrix by a smaller number of iterations to obtain the required accuracy of the numerical solution)
- 2012-11-12 21:37:19下载
- 积分:1
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channel-coding
无线通信中信道编码的内容,这信道编码的源程序,这是对应教材的源代码(Wireless communication channel coding content, which channel coding of the source, which is the source code corresponding textbook)
- 2014-08-07 08:15:15下载
- 积分:1
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lagrange
用拉格朗日n次插值方法 对一系列离散点进行插值(N times with Lagrange interpolation method interpolates a series of discrete points)
- 2015-01-25 20:02:44下载
- 积分:1
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VC_and_matlab_mix_code
VC++与MATLAB的混合编程的快速实现 讨论了如何用MATLAB的complier将*.m函数编译为动态链接库DLL,供VC++使用的方法。(VC++ and MATLAB programming for fast implementation of mixed discuss how to use MATLAB' s complier to*. m functions compiled as dynamic link library DLL, VC++ for the methods used.)
- 2010-06-30 15:44:04下载
- 积分:1
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dfedit13b
实现彩色图象的读取,以及回度图象的读取,及相关的变换(Achieve color image reading, and reading back of the picture, and the associated transformation)
- 2013-12-17 15:56:27下载
- 积分:1
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Poetry-appreciation-system
Poetry appreciation system(Be able to specify the folder poetry files (text files, not less than 10) in the order of eleven appreciate, the last one poem to the next song is the first poem, the first verse is the last one before a poem.
User interface menu (or Command button) should at least include locate the folder, on a poem, The next poem, Exit 4. Tip: You can use DriveListBox, DirListBox and FileListBox controls.)
- 2015-01-08 14:05:15下载
- 积分:1
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voicebox
matlab语音工具箱的源代码语音工具箱的源代码语音工具箱的源代码语音工具箱的源代码(matlab voiceboxvoiceboxvoicebox)
- 2012-04-07 21:44:17下载
- 积分:1
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LCS
最长公共子序列的个人实验,输入两个不同的字符序列(要求必须是字母),将输出这两个字符序列的最长公共子序列。(Individual experiments longest common subsequence, enter two different sequences of characters (letters must be required), the output of the longest common subsequence of the two-character sequence.)
- 2014-01-11 23:55:57下载
- 积分:1