Histogram-equalization

第一次上传只有一部分请不要下，这个是完整的PDF。该书介绍了如何利用MATLAB去生成DSP目标代码，并详细讲解了CCS和MATLAB联合调试程序，是一本非常经典的书籍。(The book describes how to use MATLAB to generate DSP object code, and gave a detailed joint CCS and MATLAB debugger is a very classic books.)

此书籍完整归纳了matlab从基础到高级应用的常用源代码，是一本不可多得的学习matlab的电子书籍。(This book summarizes the complete matlab from basic to advanced applications commonly used source code, is a rare study matlab e-books.)

适合初学者从入门到精通matlab编程所用，带有十三个部分的源代码，层层递进，个人感觉不错！(Suitable for beginners matlab programming from entry to the proficient use, with thirteen parts of the source code, progressive layers, personal feeling good!)

LTE下行链路空分复用开环。仿真配置：16QAM调制、1/3码率Turbo编码、10MHz带宽、每个子帧一个PDCCH符号、单码字，8次迭代Turbo译码、早期终止机制、MMSE（最小均方误差）MIMO接收器，PDSCH发射端进行空分复用预编码。信道模型是LTE-MIMO信道附加AWGN信道。(LTE downlink space division multiplexing ring opening. Simulation Configuration: 16QAM modulation, 1/3 rate Turbo code, 10MHz of bandwidth, one PDCCH per subframe symbol, single code word, 8 Turbo decoding iterations, early termination mechanisms, the MMSE (minimum mean square error) the MIMO receivers, PDSCH transmitting terminal space division multiplexing precoding. Channel model is LTE-MIMO channel additional AWGN.)

重绘窗口，实现360右下角通知窗口模式demo(repaint window, you can get the representation like the way 360 do )

说明：  matlab的一些简单使用，口输入不加扩展名的文件名，该文件必须在当前搜索路径中，例如输(matlab)

说明：  基于峭度的盲源分离算法，包含画图子程序。(Based on Kurtosis algorithm for blind source separation, including the drawing subroutine.)

关于matlab基本功能，向量、矩阵运算等(Basic functions on matlab, vector, matrix operations, etc.)

基于自适应子带频谱熵的稳健性语音端点检测，自己写的，希望对大家有帮助。(based on adaptive sub-band spectrum entropy stability voice activity detection, wrote it myself, and I hope to be helpful.)

用割平面法求解整数规划。先不考虑整数约束条件，求松弛问题的最优解，如果获得整数最优解，即为所求，运算停止．如果所得到最优解不满足整数约束条件，则在此非整数解的基础上增加新的约束条件重新求解．(By cutting plane method for solving integer programming. Not considered integer constraints, the optimal solution relaxation problem, if the integer obtained optimal solution is sought, and operation stops. If the optimal solution does not satisfy the integer constraints, then on the basis of this non-integer solutions adding new constraints on the re-solving.)