File_Transfer

leach算法MATLAB仿真，程序代码详细，完全能运行(leach algorithm MATLAB simulation, detailed program code, is fully operational)

四旋翼飞控系统，包含定点，定高，自动按航迹点飞行，自动起飞，降落功能(Four-rotor flight control system)

用matlab语言读取Renix格式文件的程序代码(Read Renix format file with the matlab language code)

实现背包的最有装载，可以实现背包的最有价值(The realization of the most loaded backpack, the backpack can be the most valuable)

用matlab采集语音，信号加噪去噪，以及fft变换(With Matlab acquisition Voice, the signal plus noise denoising, and fft transform)

是基于STBC的MIMO-OFDM的MATLAB仿真，生成误码率曲线(MATLAB simulation is based on the STBC MIMO-OFDM generate BER curves)

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)

Embedded Control Systems in CC++ An Introduction for Software Developers Using MATLAB

MATLAB图像基本操作命令：imread, imwrite, imshow,figure(MATLAB Image basic operations command：imread, imwrite, imshow,figure)

里面含有vc++代码内容和MATLAB内容，有关于程序是实现人脸识别的，很好。(Content which contains vc++ code and MATLAB content about the program is to achieve recognition, very good.)