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fahanshu

于 2011-12-19 发布 文件大小:1KB
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代码说明:

  利用罚函数法求解下列问题:求f=x1^2+4*x2^2的最小值,其中要满足:x1-x2-1≤0 -x1-x2+1≤0 x2-1≤0 (Using penalty function method to solve the following questions: o f = x1 ^ 2+ 4* x2 ^ 2 minimum value, which will meet: x1 x2-1-0 or -x1 x2+ 1 or 0- X2-1 or 0 )

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fahanshu.m,1067,2011-04-26

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