VCGIS2

介绍如何在DLL中进行函数的定义，如何使用外部程序调用DLL中定义的函数。(how the DLL function for the definition, the use of external program called defined in the DLL function.)

内含服务端和客户端，服务端开启后，客户端可以与另外一个客户端进行语音录音，也可以进行广播，类似网络会议(暂不支持视频).适合想了解多媒体编程和网络编程的初学者.(Includes server and client,when server opened, the client can chat with another client also record voice, you can also broadcast to all client online, similar to the network meeting (not support video). Suited to people who want to know multi-media programming and network programming.)

并口程序 测试PC并口输入输出文件，挺不错的一个程序 分享(this is a little )

将.fasta文件中的contig进行处理的小程序，包括NodeCopyer、contig两个应用。搞基因工程的同学们可以用一下。(It s for dealing with .fasta files, which contains NodeCopyer and contig .)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

VC 实现刷新桌面实例，精选学习源码，很好的参考资料。(VC to refresh the desktop case, select learning source code, a good reference.)

Visual c++实践与提高——串口通信与工程应用篇10源代码(Visual c++ practice and improve- serial communication and project source code (Application) 10)

uff文件处理，处理DASP生成的uff文档(uff file format)

关于TP对KdDisableDebugger双机限制的解决代码。(TP limit of KdDisableDebugger double machine to solve the code.)

会发声的按钮，VC++经典编程源码，很好的参考资料。(Will sound button, VC++ classic programming source code, a good reference.)