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kalman1
kalman滤波算法的分析设计,首先分析设计模型,再进行初始化,最后进行kalman迭代计算,得到结果(kalman filter algorithm analysis and design, analysis and design models first, then initialized, and finally the kalman iterative calculations, the results)
- 2011-06-17 15:29:30下载
- 积分:1
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ISM
ISM算法示例,基本能用,还有问题,欢迎讨论(ISM algorithm for example, the basic use, there are questions, please discuss)
- 2013-10-07 20:48:08下载
- 积分:1
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music
多重信号分类算法,用于阵列天线进行空间谱估计使用,具有高分辨率特性(Multiple signal classification algorithm for antenna array spatial spectrum estimation using a high-resolution characteristics of)
- 2009-04-09 19:40:09下载
- 积分:1
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MATLAB-and-VCPP
一种matlab与VC++混合编程的方法。供初学者参考学习。可以与MATLAB通讯。(One kind of matlab and VC++ mixed programming method. Reference for beginners to learn. You can communicate with MATLAB.)
- 2011-11-02 11:24:14下载
- 积分:1
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logo1
create logo ^_^ (Matlab)
- 2011-12-28 10:47:32下载
- 积分:1
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CC1110CC2510_Example_Softwar
LSJ-CC1110/CC2510 Example Software
Packet Error Rate Application Example(LSJ-CC1110/CC2510 Example SoftwarePacket Error Rate Application Example)
- 2007-12-09 16:59:45下载
- 积分:1
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MALTAB
欧拉方法,龙格库塔方法的MATLAB程序解常微分方程(Euler method, Runge-Kutta Methods for Ordinary Differential Equations MATLAB program)
- 2011-06-01 15:07:55下载
- 积分:1
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Multi-Instance
Multi-Instance Learning matlab code
- 2013-09-24 15:00:08下载
- 积分:1
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matlab
基于龙格库塔法的Matlab数值积分函数,每一步都非常清楚完整的解释出来(Based on the Runge-Kutta method of the Matlab numerical integration function, every step is very clear complete explanation out)
- 2013-03-05 18:51:05下载
- 积分:1
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hypot
抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2014-04-25 08:18:59下载
- 积分:1