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[二次开发] ABAQUS-UMAT
说明: ABAQUS 的二次开发,详细注释说明,自学ABAQUS的二次开发(ABAQUS secondary development, detailed notes, self-study ABAQUS secondary development)
- 2020-01-01 22:55:42下载
- 积分:1
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FENZHI
分支界限费用矩阵的说明文档,非常实用,建议下载哦(Branch line cost matrix documentation, very practical, it is recommended to download Oh)
- 2013-09-13 14:24:50下载
- 积分:1
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TLBO
this is a source code written in the matlab format for the teaching learning optimization algorithm.
- 2012-03-06 01:33:42下载
- 积分:1
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cam
凸轮的程序,很好,可以随更改,可以随便变化凸轮的结构。(Cam program, well, you can with the changes, you can easily change the structure of the cam.)
- 2021-01-23 21:48:39下载
- 积分:1
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bchcode
实现了bch编码,基于有限域多项式除法,自己动手写的,大家可以看下(Based on division in galois field,relize the BCH code )
- 2013-07-25 10:27:37下载
- 积分:1
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11087 统计逆序对
说明: Description
设a[0…n-1]是一个包含n个数的数组,若在ia[j],则称(i, j)为a数组的一个逆序对(inversion)。
比如 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成:
(1)它的左半部分逆序对的个数,(2)加上右半部分逆序对的个数,(3)再加上左半部分元素大于右半部分元素的数量。
其中前两部分(1)和(2)由递归来实现。要保证算法最后效率O(nlogn),第三部分(3)应该如何实现?
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题:
(1)怎样的数组含有最多的逆序对?最多的又是多少个呢?
(2)插入排序的运行时间和数组中逆序对的个数有关系吗?什么关系?
输入格式
第一行:n,表示接下来要输入n个元素,n不超过10000。
第二行:n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分:1
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7ef682d55cf0社会力模型
行人群体疏散仿真的社会力模型,可用于做系统仿真(Social force model for pedestrian evacuation)
- 2021-03-19 16:59:19下载
- 积分:1
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Unit1
Algorithm gauss seidel load flow
- 2013-03-10 00:51:10下载
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Simple
求解速度压力耦合的Simple半隐式迭代方法,该方法在计算流体动力学中应用极为广泛(To solve the pressure velocity coupling Simple semi-implicit iterative method, the method applied in the Computational Fluid Dynamics an extremely wide range of)
- 2021-01-05 09:08:54下载
- 积分:1
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usermat
ANSYS二次开发考虑损伤的材料模型子程序(ANSYS subroutine)
- 2020-12-01 09:49:27下载
- 积分:1