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material-de-comp[1].-grafica
Books of Graphics Computers
- 2014-11-15 03:22:43下载
- 积分:1
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netcheck
海明码发送与接收程序 测试信道的可靠性 可单独设立监听端口(Hamming code to send and receive testing the reliability of channel can be set up to monitor a separate port)
- 2007-12-18 15:02:09下载
- 积分:1
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emailparser
解析email的源代码。
mine协议
解码译码(analytic email source. Mine agreement decoder decoding)
- 2006-10-22 14:00:09下载
- 积分:1
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Final-Game
"Guess The Number" Gae For Beginers.
- 2013-12-12 21:10:34下载
- 积分:1
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UART_GUI
RS232通訊用GUI,可偵測PC上的所有Port供使用者選擇,並提供9600、115200兩個baud rate供使用者選擇(如需其他baud rate可自行於code內添加),提供RX、TX接收傳送功能,下方接收欄可接收第一個0x0A指令之前所有資料,右方接收欄則接收剩餘所有資料。(RS232 communication with the GUI, can be detected on all Port PC for users to choose and provide 9600,115200 two user selectable baud rate (for other baud rate can add their own in the code), to provide RX, TX reception transmission function, the receiver can receive all the information bar below before the first 0x0A command bar on the right to receive all the information you receive surplus.)
- 2014-12-22 17:51:39下载
- 积分:1
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knapsack
实现背包的最有装载,可以实现背包的最有价值(The realization of the most loaded backpack, the backpack can be the most valuable)
- 2008-12-12 10:39:41下载
- 积分:1
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china-regest-interface
中登接口字段解析,字段间距,截取,查找定位等等(china regist devest)
- 2014-09-02 19:15:28下载
- 积分:1
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Complex-trace-analysis
地震勘探复数道分析,利用这种方法,能方便地从地震记录中分离表示地震波动力学特征的若干参数,如瞬时振幅,瞬时相位,瞬时频率和视极性等。(The seismic exploration plural channel analysis, using this method, can be easily separated from the seismic records certain kinetic characteristics of seismic wave parameters, such as the instantaneous amplitude, instantaneous phase, instantaneous frequency and apparent polarity.)
- 2013-05-16 10:13:00下载
- 积分:1
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2012GoldInvestmentGuide-full
- Stone column play important role in infrastructure, improving soft soil. The behaviour of stone column, however, remains far well understood
- 2015-03-06 11:29:15下载
- 积分:1
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2DMaxima
在二维空间里有两个点A=(X1,Y1)和B=(X2,Y2),如果X1>X2并且Y1>Y2 ,我们认为A优于B,A是这个集合的最大极值点,在给定的二维空间里的N个点的集合S中,找出最大极值点。(In two-dimensional space, there are two points = A = (X1, Y1) and B (X2, Y2), if the X1 and Y1 > X2 > Y2, we think that A is superior to B, A is the biggest extreme value point of the set, in A given set of N points in the two-dimensional space S, find out the most extreme value point.)
- 2013-12-24 21:02:56下载
- 积分:1