wave_equetino_diff

to calculate a tuning parameter of dmc and mpc controller

四杆机构运动求解，可运算关节角度，角加速度等(four-bar mechanism)

说明：  是关于对角LDA算法的matlab代码，包含对角化代码和对角化LDA代码(Is a diagonal LDA algorithm on matlab code, including code and diagonalization Diagonalization LDA code)

正交频分复用系统仿真级性能分析的matlab源程序(Orthogonal frequency division multiplexing system level performance analysis simulation matlab source code)

这个是纯TURBO码性能研究的仿真程序可以在此基础上加入交织迭代以及MIMO(Turbo code performance simulation study of the accession on the basis of this iterative intertwined and MI MO)

Digital Image Processing With MATLAB

高频地波雷达单基地一阶和二阶海杂波程序，毕业设计做的东西(High-frequency surface wave radar monostatic first-order and second-order sea clutter program)

说明：  卡尔曼滤波，从Andrew D. Straw s Python 移植过来的(Kalman filter algorithm，This M code is modified from Andrew D. Straw s Python )

adaptive noise cancellation using lms algorithm

实现聚类K均值算法： K均值算法：给定类的个数K，将n个对象分到K个类中去，使得类内对象之间的相似性最大，而类之间的相似性最小。 缺点：产生类的大小相差不会很大，对于脏数据很敏感。 改进的算法：k—medoids 方法。这儿选取一个对象叫做mediod来代替上面的中心 的作用，这样的一个medoid就标识了这个类。步骤： 1，任意选取K个对象作为medoids（O1,O2,…Oi…Ok）。 以下是循环的： 2，将余下的对象分到各个类中去（根据与medoid最相近的原则）； 3，对于每个类（Oi）中，顺序选取一个Or，计算用Or代替Oi后的消耗—E（Or）。选择E最小的那个Or来代替Oi。这样K个medoids就改变了，下面就再转到2。 4，这样循环直到K个medoids固定下来。 这种算法对于脏数据和异常数据不敏感，但计算量显然要比K均值要大，一般只适合小数据量。(achieving K-mean clustering algorithms : K-means algorithm : given the number of Class K, n will be assigned to target K to 000 category, making target category of the similarity between the largest category of the similarity between the smallest. Disadvantages : class size have no great difference for dirty data is very sensitive. Improved algorithms : k-medoids methods. Here a selection of objects called mediod to replace the center of the above, the logo on a medoid this category. Steps : 1, arbitrary selection of objects as K medoids (O1, O2, Ok ... ... Oi). Following is a cycle : 2, the remaining targets assigned to each category (in accordance with the closest medoid principle); 3, for each category (Oi), the order of selection of a Or, calculated Oi Or replace the consumption-E (Or))