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Matlab
Matlab用法简介,利用它所提供的编程语言进行编程完成特定的工作。(Matlab usage profile, it provides the programming language used to program complete a specific task.)
- 2011-06-02 00:22:46下载
- 积分:1
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gprmax-geoaout
GPRMAX2.0中读取geo、out文件的命令。(file command to GPRMAX2.0 in using to read geo&out file.)
- 2013-08-19 17:07:50下载
- 积分:1
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UDRRS
This is a compact code for reliability analysis based on the stochastic response surface method (SRSM) which first uses the univariate dimension reduction (UDR) to decompose the multidimensional performance function into multiple one-dimensional univariate functions and then employes the cubic spine interpolation to approximate the one-dimensional univariate functions.. One mathematical example is solved for demonstration purpose.
- 2013-03-15 10:04:52下载
- 积分:1
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prac13
Adaptive thrsholding, OTSU method and also performing bluring in order to test for the above thresholding techniques
- 2013-12-05 11:47:45下载
- 积分:1
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Matlab-Code
use matlab obj detection
- 2015-03-28 18:29:57下载
- 积分:1
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callandput
利用二叉树及蒙特卡罗方法计算欧式美式权证的例程,需要的可自行下载(binary tree using the Monte Carlo method and the American Continental E routines, and we need to be downloaded)
- 2007-03-27 08:48:17下载
- 积分:1
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Jakes
用Jakes方法编写多径瑞利衰落信道模型(Using Jakes method to prepare multi-path Rayleigh fading channel model)
- 2010-12-28 19:53:24下载
- 积分:1
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my_Pls_Pred3
基于交叉检验的PLS算法,400组样本建模,200组样本检验(based on the cross-examination of the PLS algorithm, 400 sample modeling, testing 200 samples Group)
- 2006-12-23 19:49:58下载
- 积分:1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置!Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机;
变异位数统一取为4;
Nc=20,28,36,44,individuals for crossover(交换的个数)。Nm=1,5,10,15, individuals for mutation(变异的个数)。(To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分:1
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PR_167406042
利用隐式中心差分格式求解二维热传导方程的matlab代码(The matlab code to solve 2-dimension heat equation with implicit difference scheme.)
- 2013-11-09 19:07:49下载
- 积分:1