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fast_way
数学实验中的最速落径问题
A,B是不在一条铅垂线上的两点,在链接A,B两点的所有光滑曲线中,找出一条曲线,使得初速度为零的质点,在重力的作用下,自A点下滑到B点所需的时间最短
(Mathematical experiment steepest drop Path problems A, B is not a vertical line of two points, the link A, B two points in all the smooth curve, to find a curve, the initial velocity of the particle is zero, gravity role, and since the point A to B points decline in the time required for the shortest)
- 2008-12-20 17:35:14下载
- 积分:1
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fft_DIF_R2_eML
this i found for fft
- 2010-05-27 19:55:35下载
- 积分:1
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xinxindongtu
会跳动的红心,比较可爱版,可以编译上自己的名字(Beating hearts, lovely versions, can compile their own names)
- 2019-06-27 22:32:03下载
- 积分:1
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模式识别及MATLAB实验指导 源代码
说明: 模式识别及MATLAB实现学习与实验指导 源代码 杨杰 郭志强编(the source code of PATTERN RECOGNITION)
- 2020-02-02 22:03:56下载
- 积分:1
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M.file
programming for Omni-directional image. they are useful for novice.
- 2010-06-11 15:26:57下载
- 积分:1
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001
用于数学建模解决最短路径或者类似的优化问题(Mathematical modeling is used to solve the shortest path or similar optimization problems)
- 2013-07-31 11:29:46下载
- 积分:1
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Hamming
用MATLAB实现Hamming码的编码和译码,并设计了友好的互动界面,是学习信息论与编码很好的例子。(Hamming code with MATLAB to achieve encoding and decoding, and a friendly interactive interface design, information theory and coding to learn a good example.)
- 2010-05-22 11:17:36下载
- 积分:1
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Codestress_Recovery
a code is written to extract stress in 2D plane stress analysis
- 2012-05-27 14:25:11下载
- 积分:1
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MUSIC
负正弦加白噪声随机过程下使用MUSIC方法进行信号频率估计仿真,信号样本数去1000,估计的自相关矩阵为8阶,分别采用AIC和MDL准则估计信号源个数,并画出相应的MUSIC频率估计谱线。(Negative sine plus white noise random process method using MUSIC frequency estimation simulation, signal samples to 1000, the estimated autocorrelation matrix of order 8, AIC and MDL criteria were used to estimate the number of signal sources, and draw the corresponding MUSIC frequency spectrum estimation.)
- 2013-10-30 21:31:37下载
- 积分:1
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fwdapplicationstego
this source code based on steganography and developed in matlab. in steganography we can hide any data like images in another image.
this method based on application for madical data
- 2009-03-23 22:35:19下载
- 积分:1