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Voicesubframe
语音分帧程序,解决了MATLAB难以读取.WAV问题(Voice sub-frame process of MATLAB to solve difficult to read. WAV problem)
- 2009-06-02 03:40:33下载
- 积分:1
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matlab
MATLAB通信仿真及应用实例 很不错的 老师竭力推荐(on demand)
- 2012-05-13 16:31:38下载
- 积分:1
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Polynomial-non-polynomial
多项式和非多项式曲线拟合,MATLAB的经典案例 (Polynomial and non polynomial curve fitting)
- 2013-11-30 21:30:23下载
- 积分:1
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gauss
高斯函數方程式案例,主要是以matlab軟件來運算標準題型。(Gaussian equation case, mainly matlab software to compute the standard questions.)
- 2013-12-17 14:29:13下载
- 积分:1
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chzhi_rgb
双线性插值与最近领域插值的matlab源程序,两种算法的效果比较。(Recently, the field of bilinear interpolation and interpolation matlab source, comparing the effects of two algorithms.)
- 2009-03-30 21:51:24下载
- 积分:1
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beamforming1_SMI_ESB_givens
波束形成中运用givens旋转来查找权值的算子(Use of givens rotation beamforming operator to find the right value)
- 2012-09-08 10:58:29下载
- 积分:1
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RBF_Network
A radial basis function network is an artificial neural network that uses radial basis functions as activation functions. It is a linear combination of radial basis functions. They are used in function approximation, time series prediction, and control.
- 2011-11-09 11:53:06下载
- 积分:1
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comVision
图片印刷字符的识别(可识别多种字体)
将Matlab工作空间路径设置为本文件夹
在Matlab命令窗口内输入:
numCongnition( able1/01.jpg )
通过改图片来对不同的图进行处理,其中able1,able2,able3三个文件夹分别对应三种字体
命令窗口输出要识别的字符,并且自动弹出中间处理过程窗口
也可以运行:
num = pretreat( able1/01.jpg )
imshow(num)
直接得到预处理后的图片
再键入:
getNumber(num)
得到字符输出
(Set the Matlab workspace path to this folder
In the Matlab command window input:
NumCongnition ( able1/01. JPG)
Through change pictures to deal with different figure, including able1, able2, able3 three folders corresponding to three kinds of fonts
Command window output to identify characters, and automatically process among popup Windows
Can run:
Num = pretreat ( able1/01. JPG)
Imshow (num)
Directly after preprocessing of images
Type:
GetNumber (num)
Get the output character)
- 2014-02-17 16:37:48下载
- 积分:1
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Occam2DMT
说明: 此程序是OCCAM2D反演程序,可用于大地电磁法中进行二维反演。(This program is occam2d inversion program, which can be used for two-dimensional inversion in magnetotelluric method.)
- 2020-03-29 16:28:35下载
- 积分:1
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mathmodel2
说明: 1.1 背包问题
有一个徒步旅行者,已知他能承受的旅行背包的重量不超过a(kg)。设有n种物品可供他选择装入背包,这n种物品分别编号为1,2,…,n。其中第i种物品每件的重量为ai(kg),其使用价值(指一件第i种物品对旅行者来说所带来的好处的一种数量指标)为ci(i=1,2,…,n)。问这位旅行者应如何选择携带这n种物品的件数,使得总价值最大?
(1.1 knapsack problem is a hikers. he is known to travel to withstand the weight of the backpack not exceed a (kg). N Species with articles for his choice loaded backpack, n product were numbered 1, 2, ..., n. I first of which product each ai of the weight (kg), its value (i refers to a section of the types of items travelers the benefits brought by a number of indicators) for the ci (i = 1, 2, ..., n). Asked how travelers who choose to bring this product to the n pieces, making the total value of the largest?)
- 2006-04-13 18:47:43下载
- 积分:1