lab7_mrc

变分贝叶斯最小二乘法的matlab程序。(Variational Bayesian least-squares method matlab program)

精度颇高的转子临界转速及不平和响应算法，主要采用了传递矩阵法(High precision of the rotor critical speed and the uneven and response algorithms, mainly in the transfer matrix method)

锐化处理技术来加强图像的目标边界和图像细节，对图像进行梯度算子、拉普拉斯算子、Sobel算子设计，使图像的某些特征（如边缘、轮廓等）得以进一步的增强及突出(Sharpen the image processing techniques to enhance the objectives of the border and image detail, image gradient operator, Laplacian, Sobel operator design, some features of the image (such as edge, contour, etc.) can be further enhanced and prominent)

matlab信道容量仿真，包括正态，瑞利，nakagami三种信道情况下的信道容量(channel capacity matlab simulation, including normal, Rayleigh, nakagami three kinds of channels in case of channel capacity)

MATLAB Simulations for Radar Systems Design - 2004 一书对应的源代码，非常有用。(MATLAB Simulations for Radar Systems Design- 2004 a book that corresponds to the source code, very useful.)

利用matlab进行频域低通和带通滤波,效果不错(Frequency domain using matlab low-pass and band-pass filtering)

说明：  一个用于MATLAB中实现的FFT功能的码序列。很有用，有帮助(One for the realization of the FFT function of MATLAB, the code sequence. Very useful, helpful)

这时极短软件抗干扰方面的程序代码，希望对大家有帮助。(very short time the anti-jamming software code, and I hope to be helpful.)

扩散系统之浓度分布的装置。管中储放静止液体B，高度为L=10 ㎝，放置于充满A 气体的 环境中。假设与B 液体接触面之浓度为3 C 0 0.01mol m A = ，且此浓度不随时间改变 而改变，即在操作时间内( h = 10天)维持定值。气体A 在液体B 中之扩散系数为 D m s AB = 2×10− 9 2 。试决定以下两种情况下，气体A溶于液体B中之流通量(flux)。 (a) A 与B 不发生反应； (b) A 与B 发生以下之反应 A+ B→C ， A A − r = kC 其反应速率常数k = 2×10− 7 s− 1。 (Diffusion system of concentration reference device shown in Figure 3. Tube in the store still liquid B, L = 10 cm height, placed in full A gas environment. Assuming the contact surface of the liquid with the B concentration of 3 C 0 0.01mol m A =, and this concentration does not change with time and change, that is, the operating time (h = 10 days) to maintain constant. Gas A in liquid B, the diffusion coefficient D ms AB = 2 × 10-9 2. Decided the following two test cases, the gas dissolved in liquid B in the A liquid (flux). (A) A and B do not react (b) A and B of the following reaction occurs A+ B → C, AA- r = kC, the reaction rate constant k = 2 × 10-7 s-1.)

This method usually increases the global contrast of many images, especially when the usable data of the image is represented by close contrast values. Through this adjustment, the intensities can be better distributed on the histogram. This allows for areas of lower local contrast to gain a higher contrast. Histogram equalization accomplishes this by effectively spreading out the most frequent intensity values.