DSPview3

Measuring Operational Risks using Fuzzy Logic Modeling

因此假设了一种机动目标模型：初始匀速直线阶段、匀速圆周运动阶段、返回匀速直线阶段，在此过程中线速度大小?v?保持不变。利用扩展卡尔曼（extended kalman filter, EKF）滤波算法进行定位跟踪，仿真结果表明，该假设模型既符合机动实际，又便于数学处理，并且滤波算法过程稳定，具有较快的收敛速度和较高的定位精度，提高了机动目标跟踪的精度和系统的实时性。(This paper proposes a maneuver target model: the initial phase of the uniform linear, uniform circular motion stage, returning to uniform linear stage, and the size of the line speed v remaining unchanged in this process. The extended Kalman filter (EKF) was used to track position, and simulation results show that the model is in line with the actual motor and easy to deal with the mathematics. The algorithm is stable and has rapid convergence rate and high positioning accuracy to improve the accuracy of the mobile target tracking and real?time system.)

基于Matlab的0_1背包问题的动态规划方法求解(Based on the Matlab 0_1 knapsack problem, dynamic programming method for solving)

数字信号处理实验，IIR滤波器，内含有matlab实验m文件以及实验报告，供大家参考。(Digital signal processing experiment, IIR filter, contains matlab experiment m documents and the experiment report for your reference. )

说明：  详细说明：语音信号的短时分析，主要包括：分帧、短时能量、短时平均幅度、短时过零率、短时自相关函数、短时幅度差、倒谱、复倒谱、lpc系数、lpc谱估计等 绝对保证质量，是保研后导师布置的一些基础程序(Details: short-time speech signal analysis, including: framing, short-term energy, short-term average rate, short-time zero crossing rate, short-time autocorrelation function, short-term magnitude difference, cepstrum, complex cepstrum, lpc coefficient, lpc absolute guarantee of the quality of spectral estimation, is the security arrangement of some of the research base after the mentor program)

pskmodu does modulation

一个基于Simulink及GUIDE的PID控制界面呢DEMO.用户可以从面板上修改PID参数，直接仿真出PID结果(A demo application using simulink &GUIDE to accomlish PID control.Users can modify KP,KI,KD from the GUI for their own desired simulation conditions.)

optiFDTD计算MIM波导缺陷结构，这是源文件

基于canny边缘检测，模糊c均值聚类的图像分割(Canny edge detection based on fuzzy c-means clustering image segmentation)

一个简单的优化案例。求解下面的带有等式约束和简单的边框约束(box constraints)的优化问题： minx,y(x?1)2+(y?2)2s.t.0≤x≤3,1≤y≤4,2x+3y=5(A simple optimization case. To solve the following with equality constraints and simple edge constraint optimization problem (box constraints): Minx, y (x - 1) 2+ (Y - 2) 2s.t.0 = x = 3,1 = y = 4,2x+3y=5)