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89Java
javo no chinã o ffhjk nnm
- 2010-01-27 08:23:55下载
- 积分:1
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javaweb+mysql网络在线考试系统.rar
【实例简介】
- 2021-05-18 10:33:17下载
- 积分:1
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jsp_shop
网上交易系统的源代码 实现过程 采用STRUTS框架(Online trading system to achieve the process of source code using STRUTS framework)
- 2009-07-13 17:45:58下载
- 积分:1
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JAVA网络通信系统的研究与开发
说明: 本课题是应用了计算机网络通信技术和JAVA网络编程的基础知识,以JAVA为平台,利用Eclipse开发工具,并使用SQL Server 2000管理数据库数据开发出的基于Socket的网络即时通信系统。(论文+源代码+开题报告)(This project is based on the basic knowledge of computer network communication technology and Java network programming, using Java as the platform, using eclipse development tools, and using SQL Server 2000 management database data to develop a socket based network instant communication system. (paper + source code + opening report))
- 2020-03-16 21:47:36下载
- 积分:1
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AddressBook
课程设计-- 通讯录。。用NetBeans编写(Curriculum design- Address Book. . Prepared using NetBeans)
- 2008-05-27 02:46:28下载
- 积分:1
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ownerElement02
this is set by subclasses, but don t make it public.
- 2014-02-25 11:22:56下载
- 积分:1
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javamail
基于朴素贝叶斯的一个具有图形界面的垃圾邮件过滤系统(A spam filtering system based on Naive Bayes)
- 2018-03-07 11:38:41下载
- 积分:1
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ThreeInOne
插值演示,牛顿插值,拉格浪日插值,三次样条插值(interpolation demonstration of Newton's interpolation, the waves of Rugby Day interpolation, cubic spline interpolation)
- 2020-12-02 20:09:25下载
- 积分:1
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Ellipsoid
编写一个Ellipsoid类,用于椭球体的表示,其中定义三个私有变量表示一个椭球体的长半轴a短半轴b和扁率apha(Write a Ellipsoid class, used to represent the ellipsoid, which defined three private variables represents an ellipsoid semimajor axis semiminor axis B and a of APHA)
- 2017-10-16 04:39:27下载
- 积分:1
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Java进阶篇课设
实现扑克牌,一副牌中抽去大小王剩下52张(如果初练也可只用1~10这40张牌),任意抽取4张牌(称牌组),用加、减、乘、除(可加括号)把牌面上的数算成24。每张牌必须用一次且只能用一次,如抽出的牌是3、8、8、9,那么算式为(9-8)×8×3或3×8+(9-8)或(9- 8÷8)×3等。(In order to realize playing cards, 52 cards are removed from a deck (only 40 cards can be used for the first practice). Four cards are randomly selected (called card groups). The number on the deck is calculated as 24 by adding, subtracting, multiplying and dividing (brackets can be added). Each card must be used once and only once. If the drawn card is 3, 8, 8, 9, the formula is (9-8)*8*3 or 3*8+ (9-8) or (9-8 8)*3)
- 2020-12-31 16:18:59下载
- 积分:1