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新建 DOCX 文档
说明: 运用newmark法计算车桥耦合振动
桥取4阶模态,车为单自由度,车速5m/s,车辆,桥梁参数已经带入矩阵(Calculation of coupling vibration of vehicle and bridge by Newmark method)
- 2020-11-05 20:59:50下载
- 积分:1
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pv_model_simulink_R2006b
te simple model form pv
- 2011-02-07 15:32:51下载
- 积分:1
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光场matlab
模拟光场成像MATLAB 利用光场成像原理对图片模拟(light field,Simulated optical field imaging,
Using the principle of optical field imaging to simulate the picture)
- 2020-12-07 09:39:21下载
- 积分:1
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RotationForest
随机改变一个矩阵的行的顺序生成新矩阵 保持数据不变(Randomly changing the rows of a matrix to generate a new matrix)
- 2013-08-21 20:51:58下载
- 积分:1
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JPDAF
教你如何利用matlab仿真JPDA算法(Teach you how to simulate JPDA in matlab)
- 2013-03-24 14:58:55下载
- 积分:1
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K-L
说明: 基于K-L算法的人脸识别matlab程序代码(KL-based face recognition algorithm matlab code)
- 2008-12-03 17:30:05下载
- 积分:1
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Archive
Matlab code image processing GUI Histogram Gray-Scale Binary
- 2014-10-04 14:56:46下载
- 积分:1
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respm
采用线性加速度法求地震波的反应谱,可同时求加速度、速度、位移反应谱以及放大系数(Method for the linear acceleration response spectrum of seismic waves, which can find the acceleration, velocity and displacement response spectra and amplification factor)
- 2011-10-14 16:56:40下载
- 积分:1
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MATLAB_ISIGHT
基于MATLAB_ISIGHT动力总成悬置系统仿真分析与优化(Simulation analysis and optimization of powertrain mounting system based on MATLAB_ISIGHT)
- 2017-06-27 13:47:15下载
- 积分:1
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91315v00_BPU_us
Relaying and orthogonal frequency division multiple
access (OFDMA) are the accepted technologies for emerging
wireless communications standards. The activities in many
wireless standardization bodies and forums, for example IEEE
802.16 j/m and LTE-Advanced, attest to this fact. The availability
or lack thereof of efficient radio resource management (RRM)
could make or mar the opportunities in these networks. This
paper therefore provides a comprehensive RRM algorithm for
OFDMA-based multi-cellular fixed relay networks in a way to
ensure fairness among users with minimal impact on the network
throughput (in contrast, pure opportunistic RRM techniques
always favor users with good channel conditions
- 2010-09-03 16:25:39下载
- 积分:1