-
apf51
针对三相桥式整流电路的谐波和无功功率的特点,提出几种滤波方案,并进行比较,最终确定了用有源滤波方案。对于有源滤波器,本论文从结构上比较后选用并联电压型有源滤波器。(The thesis introduces several kind of filter schemes, which is aimed at the harmonic characteristic of three-phase bridge rectifier circuit .After comparison,the thesis chooses the active filter scheme,in view of the active filter, after the comparesion of structure,finally, the thesis chooses the parallel-voltage active filter.)
- 2013-01-30 15:45:59下载
- 积分:1
-
PN-code-synchronization-simulation
直接序列扩频伪码跟踪simulink仿真程序,仿真PN码捕获,跟踪过程完整过程。(Direct sequence spread spectrum code tracking simulink simulation program, emulation PN code acquisition process complete process of tracking.)
- 2014-10-18 18:11:13下载
- 积分:1
-
8puzzle
用Pology语言解决八段数码问题,可以正确运行,对初学者的学习有所帮助(Eight out of digital solutions with Pology language problem, you can run properly, help for beginners to learn)
- 2011-11-08 09:08:30下载
- 积分:1
-
1
直接序列扩频代码,完成直接序列扩频的扩展功能(Direct sequence spread spectrum code to complete the extended functionality of direct sequence spread spectrum)
- 2013-10-22 16:11:30下载
- 积分:1
-
icaMS
fastica用于信号处理系统的源码程序,希望大家多分析多处理(FastICA for the source signal processing systems process analysis of more than hope more than deal with U.S.)
- 2007-10-17 20:42:02下载
- 积分:1
-
HuMoment
hu不变矩 基于形状的图像检索 很有用的程序 欢迎大家下载(hu bu bian ju wen jian jian suo hen you yong de xiao cheng xu)
- 2010-12-10 10:53:29下载
- 积分:1
-
MRC
分集最大比合并系统,对应有SISO,SIMO,简单明了,具有很大的价值。(diversity,MRC,including siso and simo,it is simple but useful.)
- 2012-03-22 09:17:28下载
- 积分:1
-
octree-based-codes
该程序介绍了有关八叉树编码的基本编程知识,对于初级学者易懂易学。(This program introduces the octree encoding basic programming knowledge, which ishelpful for junior scholars to understand.)
- 2014-10-21 19:19:45下载
- 积分:1
-
Newton_Raphson_method_1
牛顿拉夫逊的matlab程序,可以用,已验证。(Newton Raphson method)
- 2014-11-01 19:29:40下载
- 积分:1
-
mofang
魔方还原程序,主函数为Cube,采用CFOP,还原步骤为88步左右,底面十字未优化;采用留个3*3矩阵,前面为froo(数字3),后面为baa(数字-3),左面为leff(数字-2),右面为rigg(数字2),上面为upp(数字0),下面为doo(数字1),(Cube restore process, the main function of Cube, using CFOP, the reduction step is 88 steps or so, the bottom cross unoptimized adopt leave a 3* 3 matrix, in front of froo (figure 3), followed by the baa (figure-3), left the leff (digital-2), the right of rigg (figure 2), at the upp (number 0), following the doo (figure 1),)
- 2013-11-01 14:41:59下载
- 积分:1