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DE
说明： DE 生物进化算法的matlab实现，一类优化仿生算法(DE biology evolutionary algorithm matlab implementation, a class of bionic optimization algorithm)
- 2009-03-13 23:05:50下载
- 积分：1
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l_m
convolution 2/3 rate encoder
- 2010-02-26 14:05:17下载
- 积分：1
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lssvm
实现最小二乘支持向量机编程，训练样本有97个，测试样本10个，还带自身的sig2和gam的优化(Realization of least squares support vector machine programming, there are 97 training samples, 10 samples tested, but also with their own gam sig2 and optimization)
- 2015-02-05 11:48:11下载
- 积分：1
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Matlab-picture
Matlab绘图系列之高级绘图，可以画特殊的图像(Matlab Mapping Series High drawings, special images can be painted)
- 2008-12-20 11:17:10下载
- 积分：1
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Robotics
Keywords: colahi, virtual reality (Simulate 3-bar robotic arms with Virtual Reality toolbox)
- 2009-05-14 04:51:45下载
- 积分：1
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feature-extraction
抽取颜色，纹理等特征构成210维的特征向量(Extract color, texture and other characteristics to construct 210-dimensional feature vectors )
- 2011-05-23 10:48:30下载
- 积分：1
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power_xfosaturable
功率电子领域matlab仿真文件，已经验证过，程序运行正常(Power electronics field matlab simulation file, has already been verified, the normal operating procedures)
- 2013-08-26 22:24:13下载
- 积分：1
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gcc
Generalised Cross Correlation Algorithms. It is useful to estimate the time delay in almost all situations
- 2013-12-03 18:16:56下载
- 积分：1
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EM_Algorithm
EM算法，高斯混合模型的算法，很实用.里面附有很全的代码，包括实例(Author : Shujaat Khan
Data Entry
Step 1 : Initial guess
Step 2 : Expectation Step computes the responsibilities
Step 3 : Maximization Step compute the weighted means and variances)
- 2021-04-12 16:28:58下载
- 积分：1
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radon_ambiguity
％radon transform
clear all
％
N=800
n=1:N
fs=200
t=n/fs
x1=exp(j*2*pi*(5*t+0.5*5*t.^2))
x2=exp(j*2*pi*(5*t+0.5*15*t.^2))
x=x1+x2
％N=length(x)
％ ambifunb(x )
％*****************************************RAT
naf=ambifunb(x)
htl(abs(naf))
％ [wh,rho,theta]=htl(abs(naf))
colormap([0,0,0])
％ xlabel( 极半径 )
％ ylabel( 角度 )
％**************************************％找出峰值点的坐标,计算初始频率和调频斜率(正确)
％找出峰值点的坐标
b=max(max(wh))
[u,a]=find(wh>=0.8*b)
( Radon transformclear all N = 800 n = 1: N fs = 200 t = n/fs x1 = exp (j* 2* pi* (5* t+ 0.5* 5* t. ^ 2)) x2 = exp ( j* 2* pi* (5* t+ 0.5* 15* t. ^ 2)) x = x1+ x2 N = length (x) ambifunb (x)***************************************** RATnaf = ambifunb (x) htl (abs (naf)) [wh, rho, theta ] = htl (abs (naf)) colormap ([0,0,0]) xlabel (polar radius) ylabel (angle)************************************** to find the coordinates of the peak point, calculating the initial slope of the frequency and FM (right) find the peak point of the coordinates b = max (max ( wh)) [u, a] = find (wh)
- 2008-05-06 21:56:10下载
- 积分：1
