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delphi 猜数字游戏,有兴趣的可以参考学习(delphi game code)

实现连连看游戏的算法。采用递归的算法找实现，很参考价值。(Achieve Lianliankan game algorithms. Find a recursive algorithm implementation, it is reference value.)

windows平台的游戏手柄编程源码，有很强的实用性。(Gamepad programming source code, has a strong practical.)

一个简单的贪吃蛇，希望多初学者有点帮助，就用了for循环写的(A simple snake, hope to beginners a little help, the program only used for the cycle to write)

使用QT实现扫雷，包括中键等功能。界面风格与windows扫雷类似(To use QT achieve demining, including the key functions)

非图形版的小巧玲珑的Hangman! 不一样的感觉！(non-graphic version of the small size of Hangman! Not the same feeling!)

用matlab实现的一个打地鼠的游戏，建议大家下载后学习一下，可以学到关于图像移动，鼠标捕捉，figure等方面的实际操作(Using matlab to achieve a fight to control the game, we recommend that you download to learn about, you can learn about the image moves, mouse capture, figure and other aspects of the actual operation)

说明：  在Windows平台上用C++开发的一款游戏，源代码已经打包(A game application developed with C++ progamming language on Windows OS.The source code is be contained.)

1000y的相关内容 1000y related content

Background Given a set of rectangles {R1, R2, …, Rn}, compute the area of their common intersection. i.e., Area(R1∩R2∩…∩Rn) The edges of the rectangles R1, R2, …, Rn, are either vertical or horizontal lines. For example, the intersection of 4 rectangles, R1, R2, R3, and R4, in the following figure is the shaded rectangle. Input The input contains (N + 1) lines. The first line specifies the number of rectangles N, where 1 < N < 1000. Since the sides of the rectangles are parallel to the x-axis and y-axis, each rectangle is bounded by the lines x = x1, x = x2, y = y1 and y = y2 and each subsequent line of the input file thus specifies one rectangle in the following format: x1 x2 y1 y2 such that 0 <= x1 < x2 <= 10000 and 0 <= y1 < y2 <= 10000, and x1, x2, y1 and y2 are integers. Output The output file contains the area of the intersection of all the rectangles.