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RC4
对RC4加密解密代码,可以自行修改密钥!类可以直接调用(RC4 encryption and decryption code, you can modify the key! Class can be called directly)
- 2020-10-13 23:17:31下载
- 积分:1
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DES-PIC-CBC
DES加密方法加密BMP图像,CBC方式实现。(DES encryption methods encryption BMP image, CBC way.)
- 2020-10-09 20:47:34下载
- 积分:1
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VMp
VMp——一款可以超强保护文件防止破解的加壳工具,软件设计员的绝佳伴侣!
(VMp- a super-protected files can be packed to prevent cracking of the tools, software designers the perfect partner!)
- 2010-10-23 09:39:51下载
- 积分:1
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RSA
RSA算法的解密和加密,用扩展的欧几里得算法求乘法逆元(rsa)
- 2010-06-20 13:05:12下载
- 积分:1
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Protect.x.src
加密程序的,实现了对代码的抽取乱序,区段加密和IAT的处理。
(Encryption procedures, the code of the extraction sequence, block encryption and IAT processing.)
- 2015-06-30 17:11:18下载
- 积分:1
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DESEncryptionDecrypt
编写的DES 对称加解密技术,可随时进行明文密文之间的转换,有需要的朋友可以下载测试!本人目的打算对后台数据库的敏感信息字段用该方法加密,然后用软件权限控制读取,这样即使直接SQL后台取数,也得不到明文数据。(Write DES symmetrical encryption technology, may at any time for conversion between plaintext cipher, friends in need can be download test! I purpose going to the backstage database of sensitive information field with the method of encryption, and then use software to read access control, so even if the SQL backend access directly, also can not get clear data.
)
- 2013-10-15 09:51:35下载
- 积分:1
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ATSHA204
atmel系列加密芯片资料,ATSHA204芯片手册。希望对编写驱动的朋友有所帮助!(Atmel series data encryption chip, manual ATSHA204 chip. Hope to write a driver for friends to help!)
- 2016-03-01 15:29:14下载
- 积分:1
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aes
aes源码。加密的高级标准。。。。。。。。。。(aes)
- 2010-09-19 09:29:27下载
- 积分:1
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ASFDSAF
题目:某个公司采用公用电话传递数据,数据是四位的整数,在传递过程中是加密的,加密规则如下:
每位数字都加上5,然后用和除以10的余数代替该数字,再将第一位和第四位交换,第二位和第三位交换。
1.程序分析:
2.程序源代码:(Topic: a company USES the public telephone relay data, data is four integers, in the relay in the process is encrypted, encryption rules are as follows:
Each Numbers add 5, then use and divided by the number of 10 instead of a remnant, then the first and fourth exchange, the second and third exchange.
1. The program analysis:
2. The source code:)
- 2012-05-26 20:07:28下载
- 积分:1
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39.3
说明: 编制程序,将输入的一行字符以加密的形式输出,然后将其解密,解密的字符串序列与输入的正文相比较,吻合时输出解密的正文,否则解密失败。
加密时,将每个字符的ascii码依次反复加上“4962873”中的数字,并在32(‘’)~122(‘z’)之间作模运算。解密与加密的顺序相反。例如输入正文“the result of 3 and 2 is not 8” 结果为:
(Programming, the input line character output in an encrypted form, and then decrypted, the decrypted text sequence of characters compared with the input, output to decrypt the body of the agreement, otherwise the decryption failed. Encryption, ascii code of each character in turn repeatedly with " 4962873" in the figures, and 32 (' ' )~ 122 (' z' ) as a model between the operations. Decryption and encryption in reverse order. For example, enter the text " the result of 3 and 2 is not 8" results:)
- 2011-04-05 08:43:48下载
- 积分:1