CefSharp.Wpf.Example

ARINC-美国航空无线电通信公司（Aeronautical Radio Inc），美国军队的长期合作伙伴。ARINC664系列协议是ARINC公司负责制定的下一代航空数据网络标准。该规范分为8个部分，从不同层次对航空数据网络标准的各个方面进行了系统的定义，形成了以AFDX技术为核心的下一代航空数据网络的完整标准。(ARINC-Aeronautical Radio Inc, the U.S. military long-term partners. ARINC664 series protocol is ARINC company is responsible for the formulation of the next generation of airborne data network standard. This specification is divided into eight parts, from different levels of airborne data network standard all aspects of the definition of the system, formed the AFDX technology at the core of the next generation of airborne data network complete standard.)

文件夹给出了五个基本的dsp运行程序，基于DSP28335开发板，在CCS编程环境下给出了包括跑马灯、CPU时钟控制程序等五个完整的CCS工程文件。方便初学者学习芯片及编程语言。(The folder gives five basic DSP running programs. Based on the development board of DSP28335, five complete CCS engineering documents including horse-running lamp, CPU clock control program and so on are given in CCS programming environment. It is convenient for beginners to learn chips and programming languages.)

说明：  实现一个千兆以太网卡的NDIS的miniport驱动实例源代码 对于那些希望写一个NDIS 6.0的miniport设备驱动的开发人员来说，实例实在是太少了，只有一个DDK中的E100BEX。这里，我将选择一个当前比较流行的以太网控制器（Realtek 8111/8168/8169/8110等PCI的千兆以太网控制器），针对它们写一个NDIS6的驱动(The realization of a Gigabit Ethernet card, the NDIS driver miniport instance of the source code for those who wish to write an NDIS 6.0 of the miniport device driver developers, the example is too small, there is only one DDK in E100BEX. Here, I will choose a more popular current Ethernet controller (Realtek 8111/8168/8169/8110, such as PCI Gigabit Ethernet controller), for them to write a driver NDIS6)

很好的串口通信源程序，可以设置端口号，波特率，数据位 停止位校验位(a very complete source serial communications,it is helpful for everybody)

聊天程序的源码，对学习socket编程很有帮助。(Chat program source code, useful for learning socket programming.)

用direct show 写的个播放器，可是实现最简单的播放、暂停、停止、截图等。(show with direct write-player, but to achieve the most simple play, pause, stop, and screenshots.)

Rss reader for a web design

C8051F 單片機 USB test 上位機(USB test)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

Windows系统下，SSH加密机制，用户身份认证代码，主要用于检测用户弱口令。(Windows OS，SSH encrypt，check the user s password on line.)