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2DFDTDPML
2DFDTD TM波模拟仿真,采用CPML边界条件(2DFDTD TM wave simulation, the boundary conditions used CPML)
- 2010-10-16 11:30:38下载
- 积分:1
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exhaust_pressure
It is great model of one part of engine diesel model. This particular file contains model of exhaust manifold.
- 2011-05-10 20:08:35下载
- 积分:1
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kalmanlvbozaifangzhenzhongdeyingyong
卡尔曼滤波在仿真中的应用,低于跟踪目标有很大的作用(NNAD applied to multi-target tracking, a great help for filtering, and fusion technology)
- 2012-05-24 14:08:10下载
- 积分:1
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MATLAB
绘图典型程序 包括简单的二维 三维 六维(Typical drawing program includes a simple two-dimensional three-dimensional six-dimensional)
- 2012-06-26 08:35:41下载
- 积分:1
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shortest-path-algorithm-matlab
两种比较常见的最短路径的matlab算法 (Two of the more common of the shortest path algorithm matlab)
- 2011-05-11 16:40:29下载
- 积分:1
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vessel
Blood vessel segmentation
- 2012-10-02 18:04:44下载
- 积分:1
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Archive
duffing方程用于微弱信号检测的matlab程序。包含两种方法,一种是inline,一种是@fan。(duffing equation for weak signal detection matlab program. Contains two methods, one is inline, one is @ fan.)
- 2021-01-19 21:18:42下载
- 积分:1
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pami2010Matlab
基于matlab的optical flow calculation(Matlab-based optical flow calculation)
- 2014-10-06 16:50:41下载
- 积分:1
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dianwei1
电位电极系测井曲线,用matlab编写,可用于学测井的人参考(Potential electrode system logs, prepared by matlab, people can learn logging for reference)
- 2013-11-29 14:32:56下载
- 积分:1
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turbine3
实现含风电场RX模型的系统潮流计算,风电场采用RX模型,此模型充分考虑风力发电机的输出功率特性,比其他模型完善,在模型中将迭代过程分为两步:常规潮流迭代计算和异步风力发电机的滑差迭代计算。( In short, the algorithm carried out to simulate the wind farmas an RX bus is as follows:
1)Begin with s=snorm in each machine, snorm being the rated slip of the same. With this value, calculate the impedance Z.
2)With these values, model the wind farm as an RX bus including the admittances of the machines in the admittance matrix and in the corresponding terms of the jacobian.
3)As a result of the first power flow, the voltages in the buses can be obtained. With these, can calculate the mechanical power of the machine.
4)With the value of s, calculate the power extracted the wind with .
5)Compare both powers and, if they are not equal, recalculate,by means of (G) and go to step 2. If they are equal, he algorithm finishes.)
- 2021-04-15 16:18:54下载
- 积分:1