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PSD_Matlab
This is matlab/simulink code to develop frequency domain conversion
- 2010-09-28 20:37:29下载
- 积分:1
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separation
采用子带GMM建模和贝叶斯理论来实现单信道混合语音的分离。主要分训练和分离两个阶段(Using sub-band GMM modeling and Bayesian theory to achieve the single-channel mixed audio separation. Mainly consists of two stages: training and separation )
- 2009-10-29 09:12:53下载
- 积分:1
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mqam-demodulation
mqam demodultion code with fc,fs,fd,M and ini_phase parameter
- 2014-01-02 16:36:50下载
- 积分:1
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CDMA-Reference-Blockset
CDMA Reference Blockset,CDMA的一个英文文档(CDMA Reference Blockset, CDMA in an English document)
- 2011-04-29 15:28:12下载
- 积分:1
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zuidapipei
使用匈牙利算法实现二部图最大匹配,最终找到二部图的最大匹配(achieve the max matching in bipartite graph useing the method of Hungarian algorithm)
- 2012-06-10 20:08:41下载
- 积分:1
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equal-area-critirea
E=input( enter the generator voltage: )
V=input( enter the infinite bus voltage: )
Gx=input( enter the reactance of generator: )
L1x=input( enter the line reactance: )
L2x=input( enter the line reactance: )
L3x=input( enter the line reactance: )
L4x=input( enter the line reactance: )
Pi=input( enter the input power: )
X1=Gx+L1x+((L2x*L3x)/(L2x+L3x))+L4x
Pm1=E*V/X1
DO=asin(Pi/Pm1)
A=((L2x*L3x)/(2*(L2x+L3x)))
C=A
B=((L3x/2)^2)/(L2x+L3x)
X2=(Gx+L1x+A)+(L4x+A)+(Gx+L1x+A)*(A+L4x)/B
Pm2=(E*V)/X2
X3=Gx+L1x+L2x+L4x
Pm3=(E*V)/X3
DC=input( enter the fault clearing angle: )
Dm=(3.14-asin(Pi/Pm3))
a1=quad( sin ,DO,DC)
A1=(Pi*(DC-DO)-Pm2*a1)
a2=quad( sin ,DC,Dm)
A2=Pm3*a2-Pi*(Dm-DC)
if(A2>=A1)
disp( the system is stable )
else
disp( the system is unstable )
end
Dcc=acos((Pi*(Dm-DO)-Pm2*(cos(DO))+Pm3*(cos(Dm)))/(Pm3-Pm2))
disp( critical clearing angle: )
Dcc
- 2012-09-11 22:46:05下载
- 积分:1
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LPC111
LPC分析是进行语音分析的有效技术之一,包括语音信号采集,(about LPC)
- 2009-05-22 11:16:19下载
- 积分:1
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1
Matlab为编程、分析工具,运用上、下行链路分离正序法对60GHz射频光纤( RoF) 系统进行功率设计、计算及分配(Powerdesignanddistributionof 60GHzRoFsystem)
- 2013-05-02 19:59:15下载
- 积分:1
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FFT
短时傅立叶变换matlab分析
绝对好用的STFT程序,注释清晰,如假包换!!(Short time FFT matlab analysis)
- 2012-01-05 15:50:34下载
- 积分:1
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Computing-the-24
求DFT并做出离散函数xn的傅里叶变换图像
(Computing the 24-points DFTs of the two sequences that x1(n)=
cos(nπ/6) and x2(n)= cos(nπ/4) using a single 24-point DFT by Matlab )
- 2011-05-21 23:16:02下载
- 积分:1