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quicksort
数据结构快速排序例程代码,只要按照例子就可以很容易加入到你的程序当中。(Data Structures quick sort routine code, just follow the example you can easily add them into your program.)
- 2013-05-23 15:05:53下载
- 积分:1
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huffman
数据结构(严蔚敏版)中哈夫曼树的操作程序源代码(Of data structure (Yan Wei Min version) operating procedures in the source code Huffman tree)
- 2010-05-24 23:19:39下载
- 积分:1
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Polynomial
Polynomial基于数据结构的思想,文件比较小,可以直接运行(Polynomial based on the idea of data structures, file is relatively small and can be run directly)
- 2013-12-11 11:05:18下载
- 积分:1
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Monkeys-and-peach
Monkeys and peach,Monkeys and peach(Monkeys and peach)
- 2013-09-01 22:06:42下载
- 积分:1
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bag1
使用不同的方法解决背包问题:本算法采用的是动态规划方法,比较好的解决背包问题。(Use different methods to solve knapsack problem: The algorithm is a dynamic programming approach, a better solution to knapsack problem.)
- 2011-07-16 18:40:31下载
- 积分:1
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strcon
对于给定的n个字符串,请找出一种最佳的连接方式,使得采用该连接方式得到的字符串在所有连接的结果中,字典序最小(For a given n-string, find an optimal connection, making use of the connection string to get the results in all connections, the lexicographic minimum)
- 2011-09-02 16:52:40下载
- 积分:1
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yeschengxu
这是数据结构很重要的程序,主要是课后题的答案,和代码,功能很强大(the data struct of the book)
- 2013-12-22 23:25:14下载
- 积分:1
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1_1
最小生成树算法 克鲁斯法尔算法 球最佳路径(kulru method class maiun void cx )
- 2009-09-13 22:45:01下载
- 积分:1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型,编写函数实现以下操作:
(1)实现单向链表的创建(包括初始化)与输出操作,节点的个数及节点的数据由用户输入。
(源代码:ds3-1.c)
(2)查找给定的单链表中的第i个节点,并将其地址返回。若不存在第i个节点,则返回空地址。
(源代码:ds3-2.c)
(3)查找给定的单链表中值为n的节点,并将其地址返回。若不存在值为n的节点,则返回空地址。同时,还应通过参数传回该节点的序号。
(源代码:ds3-3.c)
(4)删除给定的单链表中的第i个节点,成功返回1,失败返回0。
(源代码:ds3-4.c)
(5)删除给定的单链表中值为n的节点,成功返回1,失败返回0。
(源代码:ds3-5.c)
(6)在给定的单链表的第i位上插入值为n的节点。
(源代码:ds3-6.c)
(7)在给定单链表的值为m的节点的前面插入一个值为n的节点。
(源代码:ds3-7.c)
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分:1
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chessboard-distance
一道poj上的问题的解答,棋盘上的距离问题。即实现棋盘上从一个点移动到王,后,兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)
- 2012-06-20 10:10:45下载
- 积分:1