msvcrt-v5

第5章 菜单、工具栏、状态栏及其相关资源ToolDemoToolDemo.rar,很不错的vc源码，有兴趣的朋友可以看看。(Chapter 5 menus, toolbars, status bar and its associated resources ToolDemo ToolDemo.rar, very good vc source, interested friends can see.)

数字系统设计自动化的代码，用于计算质立方体和选拔法 (Digital System Design Automation of code, used to calculate the quality and selection of the cube law)

OPenGL讲义，本人利用课余时间总结的的比较的好的讲义，打包下载，里面有三个哦(OPenGL handouts, I use their spare time to sum up the relatively good notes, download package, there are three oh)

usb编程资料 很少见的资料 快看看吧(usb编程资料 很少见的资料 快看看吧)

说明：  遍历文件夹并建成目录树,一个非常好的例子(Traverse Folder and build the directory tree, a very good example)

弹珠球游戏可以警醒简单的操作实现了什么跟什么~(弹珠球游?可以警醒简单的 ????实现了???)

网络编程代码，包含UDP,TCP和NET的源码，每种都保护服务器端和客户端(Network programming code, including UDP, TCP and NET source code, each protected server and client)

强烈推荐vc++环境下的实时曲线程序，老外编的，值得借鉴。里面包含说明文档，我也是一开始使用mschart发现更新数据时出现屏幕闪烁，才找到这个程序，是公开的。(Strongly recommend vc++ Environment real-time curve procedures, foreign made, and worth learning from. Which contains documentation, I also started using an updated data MSChart found when the screen flashes, only to find this program is open to the public.)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

说明：  批次圖形轉換大小到目的資料夾，不更改原始圖形檔案(Batch graphics converter to the destination folder size does not change the original graphics file)