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ct
说明: n mathematics, a wavelet series is a representation of a square-integrable (real- or complex-valued) function by a certain orthonormal series generated by a wavelet. Nowadays, wavelet transformation is one of the most popular candidates of the time-frequency-transformations. This article provides a formal, mathematical definition of an orthonormal wavelet and of the integral wavelet transform
- 2014-02-25 16:46:02下载
- 积分:1
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Turboencoding
本程序详细地描述了TD-SCDMA的Turbo编码器和Turbo译码器,对大家的学习很有帮助(This procedure is described in detail TD-SCDMA' s Turbo encoder and Turbo decoder, to all of us to learn very helpful)
- 2009-11-25 09:51:41下载
- 积分:1
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im2vc
A sample of each video resolution should be available. The images to be converted should be of same resolution or a resolution adjustment algorithm can be used. Some lines need to be changed according to the directory and requirement*.
The objective behind this program is to develop a uniform function for image to video conversion.
- 2015-01-14 22:47:18下载
- 积分:1
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buscaRed.m
This code will find the best neural network by training a lot of times and calculating the MSE
- 2010-10-19 10:43:54下载
- 积分:1
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mapprojection
matlab用于图形图像处理,小波分析等(a book oabout matlab,which can use operating picture,wavelet,etc)
- 2009-12-23 09:12:05下载
- 积分:1
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G13_PassChan_Hp_TDD
MIMO瑞丽信道,8x8,输出信号的同时输出每条信道的频率特性(MIMO Rui Lixin Road, 8x8, the output signal while the output frequency characteristics of each channel)
- 2010-08-03 09:45:19下载
- 积分:1
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MatlabGUI
一本关于matlab界面制作的书籍,很全面的从基础到深入(A matlab interface on the production of books, from basic to very comprehensive in-depth)
- 2011-06-23 10:28:55下载
- 积分:1
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MATLAB-SIMULINK
matlab和simulink的进阶书籍,适合控制类专业的学生(Advanced matlab and simulink books suitable for the control class professional students)
- 2012-10-11 09:59:38下载
- 积分:1
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18109fractal
matlab 编写的分形程序.
希望有用(fractal)
- 2009-02-26 21:00:29下载
- 积分:1
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Ritz_solution
Ritz法解决-u +u=x 0<x<1,u(0)=0,u(1)=0的有限元边值问题。精确解为u(x)=1/(exp(1)-1/exp(1))*exp(-x)+1/(1/exp(1)-exp(1))*exp(x)+x,基函数为g(i)=sin(i*pi*x)(This matlab code is used to solve the boundary value problem of the differential equation:
-u +u=x 0<x<1,u(0)=0,u(1)=0, where the accurate solution is :
u(x)=1/(exp(1)-1/exp(1))*exp(-x)+1/(1/exp(1)-exp(1))*exp(x)+x)
- 2011-05-30 20:14:35下载
- 积分:1