Classical-cryptography

题目：某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下： 　　　 每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。 1.程序分析： 2.程序源代码：(Topic: a company USES the public telephone relay data, data is four integers, in the relay in the process is encrypted, encryption rules are as follows: Each Numbers add 5, then use and divided by the number of 10 instead of a remnant, then the first and fourth exchange, the second and third exchange. 1. The program analysis: 2. The source code:)

此资料为加密芯片资料，里面有例程，是很好的资料(This data encryption chip data, there are routine, the data is good)

说明：  AES加密算法的加密部分，128位加密算法实现(AES encryption algorithm the encryption part, 128-bit encryption algorithms)

AES加解密C语言源代码，可直接运行通过，方便大家借鉴学习(AES encryption and decryption of C language source code, can be directly run by, we facilitate learning from)

加密狗 HID检测工具VBS 加密狗 HID检测工具VBS加密狗 HID检测工具VBS加密狗 HID检测工具VBS加密狗 HID检测工具VBS(Encryption dog HID VBS testing tools Encryption dog HID VBS testing tools )

GOST加密解密程序，源代码是在控制台下的，我只是把他改写成MFC了。方便操作。加密解密高手可以绕过。(The GOST encryption and decryption procedures, the source code is under the console, I just put him rewrite the MFC. Easy to operate. Encryption and decryption master can be bypassed.)

说明：  信息安全相关，经典加密算法A5，通过编译(Information security-related, classic encryption algorithm A5, through compiler)

VMPC加密解密算法。已对x86优化，其他平台也可用。(VMPC encryption and decryption algorithms. Has been optimized for x86, other platforms are also available.)

修改本程序中的U盘的序列号后，程序可以变成你自己的独立的Ｕ盘启动密匙，　只能你的Ｕ盘才能打开程序　不需要往Ｕ盘中存入任何文件，就可实现用Ｕ盘加密程序.只能通过你的U盘启动你的程序 程序中有详细的注释(Encrypt your program by a soul U-disk without saving anything in you disk Modify the program, U-disk serial number, the program can become your own independent U disk key, only you can open U disk U disk does not need to deposit any file, can be achieved U disk encryption program)

ElGamal加密算法，经过测试可以编译运行(ElGamal Encryption )