-
25222-560
TD-SCDMA的物理层规范,具体介绍了信道复用和信道编码,对信道编码流程描述很清楚(TD-SCDMA standard in the physical layer, the specific details of the channel multiplexing and channel coding. right channel coding process description is very clear)
- 2006-12-05 12:04:02下载
- 积分:1
-
PWM_Rectifier
基于simulink的PWM可控整流器,可以通过控制占空比实现所需的电压!(PWM controlled rectifier based on simulink, can be realized by controlling the duty ratio required voltage!)
- 2015-04-03 21:15:44下载
- 积分:1
-
matlab
matlab 图像锐化 图像增强 高通滤波 巴特沃斯(image enhancement matlab image sharpening high-pass filter 波巴特沃斯)
- 2010-05-22 11:49:13下载
- 积分:1
-
Desktop
The files contain good ebooks for C++ programing and for Matlab
- 2010-11-11 16:33:25下载
- 积分:1
-
TestForm
根據鼠摽位置 直接實現鼠標放大鏡功能 不用另行顯示(Mouse Magnifier direct implementation based on mouse position without further invited for display)
- 2015-02-02 14:47:06下载
- 积分:1
-
gaussmoo
高斯背景建模源代码,实现背景建模,但前景处理效果不好(Gaussian background modeling source code to achieve the background modeling, but the outlook is not good treatment effect)
- 2011-11-12 14:38:46下载
- 积分:1
-
Question1
说明: C++源代码,递归实现。原问题描述:鼓上蚤时迁到一个山洞里去盗宝,里面有n件宝贝,价值分别是a1,a2......an,并且满足ai大于a1+a2+....+a(i-1)的和。他身上有一个背包,能装的东西最大价值是K,他只能进洞一次,请问他最多能带出多少?
要求:输入K,n,a1,a2......an
输出:他能最多带出的宝物价值
(C++ Source code Recursive achieve. The original problem description: drum when flea盗宝going to move in a cave, there are n pieces of treasure, valued are a1, a2 ...... an, and to meet ai than a1+ A22B !....+ a (i-1) and. Him to have a backpack, things can hold the greatest value is K, he could only hole once, to ask him to bring out the maximum number of? Requirements: Enter K, n, a1, a2 ...... an output: he can bring out the maximum value of the treasures)
- 2008-12-02 21:07:25下载
- 积分:1
-
PVInverter_init
微型逆变器初始化,简单易学,大家互相分享源码。(Micro-inverter initialization, easy to learn, we share with one another source.)
- 2014-12-03 21:06:07下载
- 积分:1
-
PhoneMS
Phone Management System
- 2014-11-25 19:16:10下载
- 积分:1
-
MATLAB-7.X
matlab7.X程序开发以及matlab编程学习(matlab7.X program development and learning matlab programming)
- 2013-10-29 08:54:49下载
- 积分:1