zhebanchazhao

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)

思塞恩算法 常用算法之一 算法导论提及(strassen algorithm which can run correctly)

东北大学数据结构实验指导书,2014级东北大学软件学院软件工程专业(Experimental data structure, guide books, Northeastern University, Northeastern University School of Software 2014 Software Engineering)

floyd算法 数据结构 求最短路径(floyd algorithm for data structure for shortest path)

利用數據結構中的棧，實現19世紀著名數學家高斯提出的八皇后問題(Stack data structure, to achieve the eight queens problem of the 19th century, the famous mathematician Gauss)

无环连通图G=(V, E)亦称为自由树T，其直径是树中所有顶点之间最短路径的最大值，设计一个算法求T的直径(Acyclic connected graph G = (V, E) is also known as free tree T, whose diameter is the tree of shortest paths between all vertices maximum design an algorithm for the diameter of T)

该代码实现了深拷贝的问题，对于深拷贝进行了一系列的介绍，并且显示其与浅拷贝的区别。(A deep copy of the code issues a series of deep copy for presentation, and shows the difference between a shallow copy.)

八皇后算法，用的是最简单的穷举法，在VC++6.0上编写的。(Eight Queens algorithm, using the simplest method of exhaustion, in VC++6.0 written on.)

数据结构上机操作实验的实验1，线性表的基本操作！！！(the basic operation of sq of date structure)

读取数据，统计所得到的文件中每个字母的权值，创建哈夫曼树，哈夫曼编码。哈夫曼解码，解码后内容写入到指定的文件。 读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组，最终可以得到一个存放目标文件内容的数组。 将得到的数组进行字母权值的统计，统计每个字母出现的次数，次数即为每个字母的权值。 将得到的字符数组与权值数组作为创建哈夫曼树的依据，哈夫曼树根据每个字母权值的大小来创建，每个节点，包括权值、父节点、左子、右子和字母本身。 根据哈夫曼树进行编码。形成目标文件的哈夫曼编码，将此编码返回。 根据哈夫曼树得到的数组即为解码数组，解码数组作为解码的结果返回。 写入输出文件，将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入，将数组写入到相应的文件中。 (Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file. Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array. The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter. The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself. According to Huffman coding. The formation of the target file Huffman coding, this code returns. According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)