GPSanti-jamklms

This function calculates the radial derivative of an input image. Input parameters: inputImage - the image to calculate the derivative from radialFilterLength - the length of the filter to use, total length will be 2*radialFilterLength+1 centerX and centerY - the point that is considered the center of the image, for the calculation minRadius and maxRadius - the minimum and maximum radius to calculate the angular derivative for. radialApproach - set to 1 to use a radius and angle search method, or 0 for a per-pixel approach

说明：  一个基于遗传算法和MLP的例子 Generic Algorithm(one based on genetic algorithms and MLP example Generic Algorithm)

快速高斯滤波工具箱（fast guassian toolbox），具有良好的滤波效果，希望大家可以用来进行探讨。(Fast Gaussian filter Toolbox (fast guassian toolbox). good filtering effect, we hope can be used to explore.)

Radial basis function neural network for tanker ship heading regulation

该文件是包含通信系统ARMA方法的诸多程序，是信号处理的主要部分，希望对大家有帮助。(The document is ARMA methods of communication systems include a number of procedures is a major part of signal processing, and they hope to help everyone.)

说明：  包含m文件，数据示范格式等，用来计算数列多重分形维数(Including m file, data demonstration format, etc., used to calculate the multifractal dimension of the sequence)

MATLAB编程（英文影印版第二版），malab编程的经典教材，适合学习与作为工具书查阅(MATLAB programming (English version of the second edition of a photocopy), malab classic programming materials ， the book can be used as a tool for learning)

说明：  正交优化代码 两条相交线的优化matlab程序 (the code of youhua )

说明：  MATLAB 最新的时频分析工具箱1，里面包含大量的MATLAB时频分析函数(The latest MATLAB toolbox 1 time-frequency analysis, which contains a large number of time-frequency analysis of the MATLAB function)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)