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NXT-SCARA-(Two-Link-Planar-Robot-Arm)
NXT SCARA (Two-Link Planar Robot Arm)
NXT SCARA Model-Based Design based on Embedded Coder Robot NXT.
- 2013-04-30 22:11:14下载
- 积分:1
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shuzixinhaochuli-shiyan3-matlab
数字信号处理 实验3 matlab代码 东南大学(Digital Signal Processing Experiment 3 matlab code Southeast University)
- 2015-03-27 20:07:26下载
- 积分:1
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miedian
基于matlab,通过焦点计算二维中的图像灭点,以还原成三维图像。(Based on matlab, calculated by the two-dimensional image in the focus off point to restore the three-dimensional image.)
- 2014-08-24 14:40:50下载
- 积分:1
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matlab_T_F
matlab 时频分析工具箱, 对于做时频联合分析很有用(time-frequency analysis matlab toolbox for doing time-frequency analysis is useful)
- 2010-08-13 23:07:52下载
- 积分:1
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T_SAR_Wang
是王志添教授关于卫星雷达技术的介绍,对于做SAR,包括INSAR、POLSAR等的人来说是非常好的资料!(SAR)
- 2010-08-25 21:53:56下载
- 积分:1
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apf-not-corrected-25711
active power filter without any correction matlab simulink file
- 2012-05-16 21:58:23下载
- 积分:1
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monte-carlo-method
蒙特卡罗方法的计算机模拟,主要是散射方面(failed to translate)
- 2011-05-18 11:37:40下载
- 积分:1
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fem_50_heat
有matlab语言编程求解有关一种热传导方程的数值计算方法(a program which is a version of fem_50 for the time-dependent heat equation, by Jochen Alberty, Carsten Carstensen, Stefan Funken)
- 2013-01-02 21:06:12下载
- 积分:1
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Drager_codes
An example of Chaos Theory application
- 2013-04-08 13:11:30下载
- 积分:1
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matlab_FEM_dismesh
DistMesh giving a singular FEM matrix?(Hi
Anyone here with some experience of using DistMesh in finite element code? I m solving the scalar Helmoltz equation in an annular region in 2D:
rho_1 < rho < rho_2
where rho_1 is the radius of a Perfect Electric Conducting cylinder and rho_2 is where the mesh is truncated using an Absorbing Boundary condition.
Now, I ve written code to mesh the region myself (by dividing the region into annular rings and picking a fixed number of points on each ring) and I ve written another program which uses DistMesh to mesh the region. I get a nice solution using my own meshing code but the FEM matrix becomes singular when I use DistMesh. This is the DistMesh Code I used:
Circle with hole
rABC=1.5
rCyl=0.5
fdstring=sprintf( ddiff(dcircle(p,0,0, f),dcircle(p,0,0, f)) ,rABC,rCyl)
fd=inline(fdstring, p )
box=[-2,-2 2,2]
[p,N]=distmesh2d(fd,@huniform,0.04,box,[])
I tried changing box and the 0.04 value (initial edge length). But every time, the matrix becomes sin)
- 2010-06-05 09:17:55下载
- 积分:1