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Wordvccod
AppWizard has created this WordAutomation application for you. This application
not only demonstrates the basics of using the Microsoft Foundation classes
but is also a starting point for writing your application.
- 2009-10-01 06:15:34下载
- 积分:1
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POJ1007
北京大学ACM POJ1007题
实现了对字符串按逆序排列(Peking ACM POJ1007 title achieved by reverse order of string)
- 2010-11-03 00:00:52下载
- 积分:1
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mingriosft
这是C语言的初级学习的80个小例子,用于初学者的学习(This is the C language of the primary learning 80 small examples for beginners to learn)
- 2017-04-14 16:28:56下载
- 积分:1
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Dict2
Word segmentation using dictionary.
- 2011-08-27 17:40:05下载
- 积分:1
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VC-clock-source
多功能时刻钟,整点报时,还有闹钟的功能,还有些功能没有完善。(Multi-time clock, the whole point of time, as well as alarm clock function, and some feature is not perfect.)
- 2011-10-06 11:55:04下载
- 积分:1
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Jacobi
数值分析分析中 用jacobi迭代求解线性方程(Analysis of numerical analysis using jacobi iteration for solving linear equations)
- 2009-06-13 16:48:55下载
- 积分:1
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zvite-class
这是一个自己写的完整的ADO类 包含了两部分(This is a complete write their own ADO class contains two parts)
- 2017-04-01 09:37:22下载
- 积分:1
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youxiangtu
编写C程序,随机给出n*n的邻接矩阵,并打印输出邻接矩阵,以及有向图的边的个数,每个顶点的度,并判断该图中是否存在Euler回路:
(1)如果为n阶,则随机产生一个n*n的邻接矩阵;
(2)输出邻接矩阵,边的个数,每个顶点的度以及图中是否存在Euler回路。
这个题目涉及到了两个主要的知识点,一个是数据结构中的有向图的邻接矩阵的创建,还有就是离散数学中的Euler回路的判定定理。(The preparation of C procedures, were randomly given n* n s adjacency matrix and adjacency matrix printouts, as well as to map the number of edges, each vertex degrees, and determine the existence of the map Euler circuit: (1) If for n-order, then randomly generated a n* n adjacency matrix (2) output adjacency matrix, the number of edges, each vertex of degree as well as map the existence of Euler circuit. This topic relates to two main points of knowledge, a data structure of digraph adjacency matrix of creation, there is discrete mathematics in the loop to determine Euler theorem.)
- 2008-06-14 02:33:57下载
- 积分:1
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wenjiankunbanqi
这是VC++实现的一个文件捆绑软件的源码(This is a file bundled software source code VC++ achieve)
- 2012-07-12 06:07:40下载
- 积分:1
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Practice1_14
字符串交叉输入,就是将一个字符串交叉的输入到了另一个字符串当中,比如:
char a[4]="ABCD" char b[4]="abcd"
则char c[8]="AaBbCcDd"
(Cross-string input, is to cross a string input to another string of them, such as:
char a [4] = "ABCD" char b [4] = "abcd"
While char c [8] = "AaBbCcDd" )
- 2009-02-19 18:26:20下载
- 积分:1