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TD_vedyna_user_manual
车辆动力学仿真软件veDYNA的用户指南(VeDYNA vehicle dynamics simulation software user s guide)
- 2010-12-09 22:59:36下载
- 积分:1
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Visual_Studio_2010-Beginners-Guides
C++初学者必备,介绍Windows下面使用C++进行开发的常见问题,Visual Studio 2010的使用,如何创建新项目,如何调试等等。(Beginners must C++ FAQs introduced Windows following using C++ developed Visual Studio 2010 use, how to create a new project, how to debug.)
- 2013-01-15 14:55:40下载
- 积分:1
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LINGO-model
过程工业蒸汽动力系统是过程工业的重要组成部分,它的安全、稳定运行是企业安全、稳定、长周期运行的基础。蒸汽动力系统的设计水平、运行和控制性能对过程工业的能量利用率和经济性具有重要影响,研究蒸汽动力
系统设计、运行、控制各层次的集成建模优化对于指导蒸汽动力系统全面优
化具有重要意义。
(
Industrial process steam power system is an important part of the process industry, it s safe and stable operation of the enterprise security, stability, long-term operation of the foundation. Steam power system level design, operation and control performance has a significant impact on energy efficiency and economy in the process industry, research steam power system design, operation and control of all levels of integrated modeling optimization guidance for full optimization of steam power system has an important significance)
- 2014-12-02 15:02:23下载
- 积分:1
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motor
异步电机带转矩内环的转速磁链闭环矢量控制(With a torque loop, speed and flux loop induction motor vector control)
- 2015-04-13 19:33:38下载
- 积分:1
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daiyoumpptdedongxi
带有MPPT功能的光伏阵列Matlab通用仿真模型.kdh(MPPT in PV arrays with Matlab Simulation Model. Kdh)
- 2011-05-09 15:59:04下载
- 积分:1
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lda_1.3.2.tar
lda算法,用于特征降维,可以将特征映射到更加易于区分的空间(FISHER DISCRIMINANT ANALYSIS WITH
KERNELS)
- 2015-04-17 16:48:02下载
- 积分:1
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aa228
用于求一个信号的斜率,通过构造一个滤波器来实现的,绝对正确。(For seeking the slope of a signal, to be achieved by constructing a filter, absolutely correct.)
- 2012-03-29 10:11:41下载
- 积分:1
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music
空间谱估计均匀线阵music算法matlab程序(ULA program music algorithm matlab)
- 2009-03-08 17:38:06下载
- 积分:1
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simulink_matlab-fangzhenjiaocheng
simulink 仿真教程,详细介绍了simulink的仿真环境及模型的创建(simulink simulation tutorial, detailing the simulink simulation environment and model creation)
- 2011-04-19 22:57:32下载
- 积分:1
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deconvolve
deconvolution
deconvolve.m
Given a system impulse response h[n] and test response y[n], this
algorithm deconvolves the test response with the impulse response
to determine the input x[n] as X(jw) = Y(jw)/H(jw).
Eliminate some noise, but is still very rough
NOTE: Assumes all signals are the same length. Use sigcorrect.m
to equalize their lengths if they are different.
use: deconvolve(impresp,test,testresp)
variables: impresp: impulse response of system
test: test input to system
testresp: test response of system
- 2011-11-11 09:04:25下载
- 积分:1