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Persian calender mfile 1392 in matlab

该算法为fastica的c＋＋版版本，有很好的分离效果。 (The algorithm for the fastica the c++ Version, good separation.)

排队论模型仿真程序。用MATLAB实现 。欢迎大家一起讨论(Queuing theory model simulation program. Use MATLAB to achieve. Welcome to discuss with)

PLS 的Matlab代码,用于线性降维和回归分析(matlab source code for partial least squares)

Steven M. Kay统计信号处理基础一书的解答(The solution of Fundamentals_Of_Statistical_Signal_Processing)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

说明：  自适应网格划分通用程序包，美国伯克利大学开发的共享软件包。(Adaptive Mesh generic package, the United States developed at the University of Berkeley's share package.)

boost DC DC GOOD simulation

用 MATLAB控制摄像头读取图像 可以实现拍照功能(just do it)

load flow in redial distribution network