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matlab-toolbox

于 2013-08-25 发布 文件大小:21KB
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下载积分: 1 下载次数: 3

代码说明:

  Matlab 工具,各类积分,二次定积分,gquad2dggen等(Matlab tool, all kinds of points, the second definite integral, gquad2dggen etc.)

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  • GGA__SVMMA
    12行:host= gatest %在matlab的安装盘,例如c:下设置的程序源码运行结果目录。 源代码完整 ">
    2012-08-03 13:32:15下载
    积分:1
  • turbodemotool
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    2010-05-10 22:44:57下载
    积分:1
  • MxianxintiaopA
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    2012-07-20 08:59:19下载
    积分:1
  • Matlab-cPP
    ,从Matlab调用C/C++代码及C/C++调用m文件两方面,深入地研究了它们之间混合编程的原理和实现机制,并且给出了具体条件下的混合编程方法和步骤。实例表明,提出的Matlab与C/C++混合编程方法是简洁、有效的。 更多还原 (Two aspects, called from Matlab the C/C++ code, C/C++ call m files, in-depth study of the principles and implementation mechanisms of mixed programming between them, and given the mixed programming methods and steps under specific conditions. The examples show that the proposed Matlab and C/C++ hybrid programming method is simple, effective. More Restore)
    2013-03-19 14:14:58下载
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  • bch
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    2010-11-21 17:44:34下载
    积分:1
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    2009-04-03 10:37:30下载
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  • dataliink.c
    计算机网络数据链路选择性重传实验。   设计一个滑动窗口协议,在仿真环境下编程实现有噪音信道环境下两站点之间无差错双工通信。信道模型为8000bps 全双工卫星信道,信道传播时延270毫秒,信道误码率为,信道提供字节流传输服务,网络层分组长度固定为256字节。(Computer network data link selective retransmission experiment. Design of a sliding window protocol in simulation programming environment there is no error duplex communication channel between the noisy environment the two sites. Channel model is 8000bps full-duplex satellite channel, the channel propagation delay 270 ms, channel bit error rate, channel provides a byte stream transmission services, network layer packet length is fixed at 256 bytes.)
    2013-11-26 19:19:51下载
    积分:1
  • 5
    一道程序编译顺序的考题,涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的,这道题的重点在“fun((int)fun(a+c,b),a-c)) ”语句。 系统首先要确定最外层 fun()函数的实参,第一个参数的确定需要递归调用fun()函数(不妨称其为内层函数)。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
    2009-03-15 15:36:23下载
    积分:1
  • GA-paper
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    2010-03-20 09:13:17下载
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