Exercise4

用于监控vmware中的各项资源，vim25jar为6.7版本(Used to monitor resources in the vmware)

说明：  cmpp2.0 java示例，示例简单明了，除工具一个工具类文件和几个协议类文件，所有报文操作都在一个文件内，由几个方法组成，希望对刚接触cmpp开发的新手.(The example of CMPP2.0 Java is simple and clear. Except for tool class file and protocol class file, all message operations are in one file and consist of several methods. I hope to be a novice who has just come into contact with the development of cmpp.)

Pending Intent Record extends I Intent Sender. Stub Source Code for Andriod.

北大青鸟使用MVC开发租房系统Struts + servlet +jsp(Beida Jade Bird rent system developed using the MVC Struts+ servlet+ jsp)

Carte programare Java in romana

建议的安卓音乐播放器，很简单的代码，适合新手学习(Andrews recommended music player, a very simple code, suitable for novice learning)

题目：打印出杨辉三角形（要求打印出10行题目：输入3个数a,b,c，按大小顺序输出。 题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。 题目：有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数 题目：编写一个函数，输入n为偶数时，调用函数求1/2+1/4+...+1/n,当输入n为奇数时，调用函数1/1+1/3+...+1/n(Topic: Print out the Triangle (10 lines required to print out the Title: Enter the 3 numbers a, b, c, according to the order of output. Title: input array, the largest exchange with the first element, the smallest and the last element of the exchange, output array. Topic: There are n integers, to move back in front of the order m of the number of positions, finally becoming the foremost m m the number of number of topics: write a function, the input n is even, the call function evaluation 1/2+1/4+...+ 1/n, when the input n is odd, call the function 1/1+1/3+...+ 1/n)

Spring AOP 面向切面编程 开发工具IDEA, TomCat, Sql(Introduction to SpringAOP , Development tools IDEA, TomCat, SQL)

《Java How to program 第四版》 影印版。Java基础教材。(" Java How to program fourth edition of" photocopy version. Java based materials.)

基于c++ 的水果销售管理系统，使用access数据库，简单实用，方便。适合新手。(C++ based fruit marketing management system, the use of access, simple, practical and convenient. Suitable for beginners.)