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PC41
数控机床第四象限到第一象限的圆弧插补程序及界面,步长可变,位数可变(CNC machine tools fourth quadrant to quadrant circular interpolation procedures and interface, the step variable, the median variable)
- 2012-04-09 15:28:10下载
- 积分:1
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music2
music 算法解决问题续,欠估计情况下的精度(music algorithm to solve the problem continued, underdevelopment of the estimated accuracy)
- 2006-08-01 01:28:51下载
- 积分:1
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ford-max-flow
解决最小费用最大流问题,一般有两条途径。一条途径是先用最大流算法算出最大流,然后根据边费用,检查是否有可能在流量平衡的前提下通过调整边流量,使总费用得以减少?只要有这个可能,就进行这样的调整。调整后,得到一个新的最大流。(Minimum cost maximum flow problem to solve, there are generally two ways. One way is to use a maximum flow algorithm to calculate the maximum flow, then the cost side, check whether it is possible under the premise of the flow balance by adjusting the edge flow, so that the total cost can be reduced? As long as this possible, for such adjustments. Adjusted to obtain a new maximum flow.)
- 2013-08-23 23:18:43下载
- 积分:1
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jei-je33
本科毕设要求参见标准测试模型,可直接计算得到多重分形谱,一种噪声辅助数据分析方法。( Undergraduate complete set requirements refer to the standard test models, It can be directly calculated multi-fractal spectrum, A noise auxiliary data analysis method.)
- 2017-03-22 20:19:50下载
- 积分:1
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30statcom
该文件是PQ分解法,可以更有效地解决IEEE30节点系统的潮流,希望可以给广大朋友一定的帮助。(The file is PQ decomposition, can more effectively address the trend IEEE30 bus system, hoping to be helpful to the general friend.)
- 2020-12-17 20:59:12下载
- 积分:1
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fdtd
fdtd 计算二位电磁脉冲的源程序,脉冲为高斯脉冲
- 2012-04-26 15:17:18下载
- 积分:1
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Polar code_shorten
main_PC_Shorten.m
polarDec_S_Change.m
rev_shuffle.m
polarEnc.m
PCencoder.m
attachCRC.m
capacities.m
crcCheck.m
encoder.m
genSrc.m
initialize_frozen_bits.m
likelihood_rate.m
path_matrix.m
path_metric.m
paeeword: share_20180410
- 2018-04-10 10:07:08下载
- 积分:1
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matlab-dc
matlab中常用电法各种装置的电磁正演计算(matlab often electricity law of electromagnetic devices forward calculation)
- 2009-01-23 10:43:43下载
- 积分:1
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myifft2
FFT 快速傅里叶变换 matlab源代码(FFT)
- 2010-12-24 09:26:52下载
- 积分:1
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ZeroCounter
很经典的一款统计器,可以分时期统计访问量。(Statistics is a classic, you can sub-period traffic statistics.)
- 2007-10-14 23:26:16下载
- 积分:1