登录
首页 » matlab » duffing

duffing

于 2013-03-06 发布 文件大小:1KB
0 257
下载积分: 1 下载次数: 17

代码说明:

  计算duffing程序的matlab方法,可以直接引用(Method of calculating duffing program Matlab, a direct reference to)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • MATLAB_7course
    matlab课程教学资料,共大家共同学习,大家一起交流学习(matlab teaching information of common learning, with exchange of learning)
    2012-09-27 11:29:39下载
    积分:1
  • 53.online-polling-software-system
    53.online polling software system internet
    2015-04-07 09:48:44下载
    积分:1
  • MM1
    MM1排队系统的matlab仿真。整个系统的仿真采用了离散事件系统仿真,并统计稳态分布、平均队列长度,等待时间的分布以及平均等待时间等值,以与理论分析结果进行对比,得到了较为满意的结果,同时还完成了统计曲线的绘制并进行了分析。(MM1 queuing system with matlab simulation. The simulation of the entire system using discrete event simulation, and statistical steady state distribution, the average queue length, waiting time distribution and the average waiting time equivalents, compared with the theoretical analysis, have been more satisfied with the results, and also completed statistical curve is drawn and analyzed.)
    2020-12-15 10:19:13下载
    积分:1
  • my_cgs
    共轭梯度平方法的matlab代码,可用于解线性方程组(cgs method is used to solve linear functions)
    2011-11-07 15:13:48下载
    积分:1
  • OpticalFlow
    optical flow for matching and differential
    2009-03-24 05:42:18下载
    积分:1
  • akima
    克里金内插的matlab程序,简单,速度快(Kriging interpolation of the matlab program, simple, fast)
    2009-04-26 15:34:48下载
    积分:1
  • welch-snr
    谱估计的welch算法的matlab仿真(Spectrum estimation welch algorithm matlab simulation)
    2012-06-12 08:49:02下载
    积分:1
  • ALCOSP13_0040_MS_Backstepping_El_Fadili
    Backstepping controller for Doubly Fed
    2014-08-28 15:38:56下载
    积分:1
  • ex1_003
    matlab实现的推荐系统,融合机器学习的方法,出自斯坦福大学吴恩达(matlab implementation of recommendation system, the integration of machine learning methods, from Stanford University, Wu Enda)
    2013-09-22 10:03:55下载
    积分:1
  • Ritz_solution
    Ritz法解决-u +u=x 0<x<1,u(0)=0,u(1)=0的有限元边值问题。精确解为u(x)=1/(exp(1)-1/exp(1))*exp(-x)+1/(1/exp(1)-exp(1))*exp(x)+x,基函数为g(i)=sin(i*pi*x)(This matlab code is used to solve the boundary value problem of the differential equation: -u +u=x 0<x<1,u(0)=0,u(1)=0, where the accurate solution is : u(x)=1/(exp(1)-1/exp(1))*exp(-x)+1/(1/exp(1)-exp(1))*exp(x)+x)
    2011-05-30 20:14:35下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载