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c9_estimatepi
%File: c9_estimatepi.m
%有5个pi的估计,每一个都是基于500次重复随机试验,所得的pi的五个估计值用以下向量表示
%pi的估计值=[3.0960 3.0720 2.9920 3.1600 3.0480]
%如果对5个结果进平均,则pi的估计值=3.0736,这样的结果等价于2500次的试验结果。( File: c9_estimatepi.m have 5 pi estimates are based on a randomized trial to repeat 500 times the income of the five estimated value of pi with the following vector, said the estimated value of pi = [3.0960 3.0720 2.9920 3.1600 3.0480] if the results into an average of 5, then the estimated value of pi = 3.0736, so the result is equivalent to 2500 times the test results.)
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- 积分:1
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fpdepyou
hi di attached the matlab source code
- 2009-09-14 12:14:17下载
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PNGE
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coin-detection
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GOFBBlockCipher
implements the GOST 28147 OFB counter mode (GCTR).
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随机动态规划matlab程序
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pso
本文为基于matlab的粒子群算法的程序,以求函数最小值为例,讲述如何用粒子群算法求得局部和全局最优解。(This article is based on particle swarm algorithm matlab procedures, in order to the minimum function, for example, on how to use PSO obtain local and global optimal solution.)
- 2013-09-11 10:56:10下载
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2X2
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