-
QPSK-AWGN
this is simmulation QPSK modulation in AWGN channel
- 2009-12-18 01:51:34下载
- 积分:1
-
MIN
一次完成算法的最小二乘法的过程辨识代码。以m序列为输入量,用其lsim响应,作为辨识依据(One of the least squares algorithm to complete the process of identification code. To m for the input sequence with its lsim response, as a basis for identification)
- 2009-05-30 16:08:59下载
- 积分:1
-
LDPC_system
matlab 模拟ldpc系统,包括BER和SNR,BER和迭代次数的关系(matlab simulation ldpc system, including the BER and SNR, BER and the relationship of the number of iterations)
- 2012-12-30 12:11:34下载
- 积分:1
-
rgsjwl
人工网络的原理及应用讲义。讲得很详细,包括matlab仿真方法(Principles of artificial network and application notes. Very detailed, including the matlab simulation method)
- 2008-04-25 11:59:42下载
- 积分:1
-
IntroductionToAlgorithm
this book has description of introduction to algorithms.
- 2010-11-09 04:07:50下载
- 积分:1
-
ExpresssionRecognition
表情识别:Matlab程序+PDF说明文档。适合初学者(Expression recognition:Matlab sources+ PDF document.It s suitable for the beginners. )
- 2009-11-28 12:12:46下载
- 积分:1
-
ants
matlab中的蚂蚁算法又叫蚁群算法。主要解决函数优化,寻最优值问题(In matlab ,the ants can revolosion the problem about chath the rightes answer .)
- 2010-05-22 10:37:42下载
- 积分:1
-
beijingyouhua
灰色模型的背景值和求导过程的联合优化,效果非常不错(Joint optimization model and gray background value derivation process, the effect is very good)
- 2013-12-23 22:07:01下载
- 积分:1
-
matlab_FEM_dismesh
DistMesh giving a singular FEM matrix?(Hi
Anyone here with some experience of using DistMesh in finite element code? I m solving the scalar Helmoltz equation in an annular region in 2D:
rho_1 < rho < rho_2
where rho_1 is the radius of a Perfect Electric Conducting cylinder and rho_2 is where the mesh is truncated using an Absorbing Boundary condition.
Now, I ve written code to mesh the region myself (by dividing the region into annular rings and picking a fixed number of points on each ring) and I ve written another program which uses DistMesh to mesh the region. I get a nice solution using my own meshing code but the FEM matrix becomes singular when I use DistMesh. This is the DistMesh Code I used:
Circle with hole
rABC=1.5
rCyl=0.5
fdstring=sprintf( ddiff(dcircle(p,0,0, f),dcircle(p,0,0, f)) ,rABC,rCyl)
fd=inline(fdstring, p )
box=[-2,-2 2,2]
[p,N]=distmesh2d(fd,@huniform,0.04,box,[])
I tried changing box and the 0.04 value (initial edge length). But every time, the matrix becomes sin)
- 2010-06-05 09:17:55下载
- 积分:1
-
Hanning-window-filter
Hanning window filter
- 2012-11-03 13:03:45下载
- 积分:1