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说明：  某厂向用户提供发动机，合同规定，第一、二、三季度末分别交货40台、60台、80台．每季度的生产费用为 （元），其中x是该季生产的台数．若交货后有剩余，可用于下季度交货，但需支付存储费，每台每季度c元．已知工厂每季度最大生产能力为100台，第一季度开始时无存货，设a=50、b=0.2、c=4，问工厂应如何安排生产计划，才能既满足合同又使总费用最低．讨论a、b、c变化对计划的影响，并作出合理的解释(To provide users with a factory engine, contract, first, second and third quarter respectively, delivered at the end of 40, 60, 80. Quarterly cost of production (million), in which x is the quarter of the number of production. If the remaining after delivery, can be used for delivery next quarter, subject to payment of storage fees, for each element c of each quarter. The largest known plant production capacity of each quarter to 100, the beginning of the first quarter of stock, set up a = 50, b = 0.2, c = 4, asked how to arrange the production of the factory plans to meet the total cost of the contract makes the minimum . Discussion of a, b, c of the impact of change on the plan and make a reasonable explanation)

qunser公司matlab例程，包括自控实验的例程，quanser公司很多设备的matlab控制程序，可以作为研究代码自动生成的参考资料。(qunser company Matlab routines, including self-control experiment routines, many devices quanser company Matlab control procedures, can be used as the code automatically generated reference.)

3 STAGE NETWORK MATLAB CODE FOR TELECOMMINCATION ENGG

Implementation bayes

应急物流系统中的定位-路径优化!!!!!!!(The positioning of emergency logistics system- path optimization!!!!!!)

同步MIMO-OFDM系统,分为SNR=10和SNR=20两种参数进行仿真。MATLAB程序。(Synchronous MIMO-OFDM system, into SNR = 10 SNR = 20 and two kinds of parameters for simulation. MATLAB.)

three LCCWIN-32 macro-implementations for measuring cpu-cycles:

模拟通信系统中，幅度调制及频率调制的代码，调制与解调，应用matlab实现。(Analog communication systems, amplitude modulation and frequency modulation code, modulation and demodulation, the application of matlab.)

matlab求数值积分以及数值求导函数源码(Matlab for numerical integration and numerical derivation function source code)

差分方程求解 实验步骤： 主界面下进入实验五的“差分方程求解”子系统,输入希望看到的输出样点数 输入差分方程系数向量 输入顺序为：，。其中 N+1 为差分方程两边系数最大数目，如果有一边输入系数个数小于 N+1，将按不足系数为零计算。 输入系统初始状态向量 输入顺序为 鼠标单击确定按钮，以数值和图形两种方式显示单位冲激响应和输出响应 3） 确定差分方程形式：y(k)-y(k-1)+0.35y(k-2)=2x(k)-x(k-1)，(Experimental steps for solving differential equations: the main interface into five experimental " differential equation" subsystems, would like to see the output of input sample points difference equation coefficient of input vector input sequence as follows:,. One of N+1 differential equations for the maximum number of factors on both sides, if there is one less than the number of input coefficient of N+1, the calculation will be less than zero coefficient. Initial state vector input system for the importation of the order of the mouse button to click OK to both numerical and graphical display unit impulse response and output in response to 3) to determine the form of differential equation: y (k)-y (k-1)+0.35 y (k-2) = 2x (k)-x (k-1),)