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GM3101Ver3[1][1].1display
成都国腾辉GM3101倒车雷达专用芯片显示源程序(Chengdu, China Tenghui GM3101 reversing radar dedicated chip source)
- 2012-10-22 00:02:47下载
- 积分:1
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read_vrml
一个Matlab程序,用它可以读取WRL文件的源码,并且可以显示(A Matlab program, using it can be read by the WRL document source, and can show)
- 2020-07-22 14:58:45下载
- 积分:1
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CalculateUserPosition
求解用户位置的Matlab函数代码,利用伪距测量用户位置的仿真计算(The Matlab function for solving location of the user code, the use of pseudo-range measurement location of the user s simulation)
- 2009-11-08 10:13:01下载
- 积分:1
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the.expendables.(2010).eng.1cd.(3787046)
it is a matlab guide , can be useful for mini projects and final projects.It provedto be very much useful for me ,hope u guys will make use out of it .
- 2010-09-20 17:45:47下载
- 积分:1
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ABC0317
基本蜂群程序,实测可用~~~~~~~~~~~~~~~~~~~~~~~~~~~(basic ABC)
- 2012-05-08 09:07:55下载
- 积分:1
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single_phase_grid_pv
matlab code for Residential Grid connected PV system with MPPT
- 2015-02-05 13:42:05下载
- 积分:1
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calculate_angle
给定地理坐标(经度、纬度),求出一年中每一天的太阳高度角和方位角(Given geographic coordinates (latitude and longitude), each day of the year, the sun s elevation angle and azimuth angle)
- 2016-06-04 13:02:47下载
- 积分:1
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mc_cdma
自己用Simulink做的mc_cdma链路仿真,运行结果还不错,有需要的可以参考一下(Their own to do with the mc_cdma link Simulink simulation, the results also is true that there is a need to look at the can)
- 2007-10-12 15:29:11下载
- 积分:1
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MATLAB
Matlab编程基础及应用,是学习matlab的好材料(Matlab programming basic and applied, is a good material to learn matlab)
- 2010-05-29 19:03:50下载
- 积分:1
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ieee754_32
Converts a floating point value to IEEE 754 32 bit binary representation.
Sign Bit: 1
Exp: 2 to 9
Frac: 10:32
Single-precision floating-point format is a computer number format that occupies 4 bytes (32 bits) in computer memory and represents a wide dynamic range of values by using a floating point. In IEEE 754-2008 the 32-bit base 2 format is officially referred to as binary32. It was called single in IEEE 754-1985. In older computers, other floating-point formats of 4 bytes were used.
For example, the 32-bit floating point bit pattern 1 01111101 00101100000000000000000 is interpreted as the following:
(− 1)1 × (1 + 0.34375) × 2(125–127) = -1.34375× 2− 2 = -0.3359375
- 2013-09-07 22:20:32下载
- 积分:1