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3Ddistance
计算三维坐标各点相互距离,结果存在对角阵中(calculate 3D points distance between eachother!)
- 2013-05-20 22:44:16下载
- 积分:1
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sg
说明: 仿真已测试过,波形非常好。是双管正激电路参考的经典案例。(THAT IS THE GOOD DESIGN)
- 2017-06-22 10:51:52下载
- 积分:1
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cellulars
含19个小区的多小区系统大尺度衰落建模。(With 19 multi-cell cellular system by the decline of large-scale modeling.)
- 2010-07-08 14:07:54下载
- 积分:1
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papr-pour-ofdm
In this section, the PAPR performance of the proposed
algorithms is shown. To evaluate the PAPR performance, the
CCDF is employed. The specification detail of simulation
parameters is given in TABLE I.
In Fig. 5 is shown the PAPR with a PTS method (U = 8) and
conventional PTS (U = 4) are improved 4.3 dB and 2.6 dB
from ordinary MIMO-OFDM signal when CCDF = 10− 4
respectively and Fig. 6 is shown the PAPR with an optimal
PTS method in case of 128 subcarriers.
- 2013-11-26 21:08:20下载
- 积分:1
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text
this a program that gets data from excel and sets zero to blank cels.
- 2010-08-03 05:30:45下载
- 积分:1
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sim1
Simulink model for embedded matlab function
- 2012-03-28 08:17:16下载
- 积分:1
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fig1_13
合成孔径雷达sar信噪比相对于不同脉冲长度的MATLAB仿真程序,最后结果以图表形式给出(Synthetic aperture radar sar signal-to-noise ratio relative to different pulse lengths MATLAB simulation program, the final result is given in chart form)
- 2012-09-26 17:29:17下载
- 积分:1
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fuse_lap
拉普拉斯金字塔变换的融合算法,对于灰度图像可用(lap_)
- 2009-05-13 16:54:38下载
- 积分:1
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annMatlab7p3
说明: 神经网络与matlab7的实现
配套资料下载
.m格式(neural network and the realization matlab7 supporting information downloaded. M format)
- 2006-04-15 00:51:05下载
- 积分:1
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yuanzhut
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*p),k是热传导系数0.6006焦/(米*秒*度))
初始条件:t=0时水等于100度
边界条件:1.上下壁都是自由冷却,第三类边界条件,周围温度保持在20度(H=k/h,h取1)
2.杯壁绝热,第二类边界条件
(cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, the second boundary condition)
- 2007-04-11 00:14:47下载
- 积分:1